Question

The distance D that a spring is stretched by a hanging object varies directly as the weight W of the object. If a 27-kg object stretches a spring 53 cm, find the distance when the weight is 13-kg. Round your answer to the nearest whole centimeter.

Answer 1

Answer:

The distance when the weight is 13-kg is $25.51$ cm

Step-by-step explanation:

$27$ Kg mass of object stretches the spring by $53$ cm

$1$ kg mass of object stretches the spring by $\frac{53}{27}$ cm

$13$ kg mass of object stretches the spring by $\frac{53}{27} * (13)\\= 25.51$ cm

Answer 2

Cross multiply: 27x = 53*13 
x = 53*13/27 = 25.52 
Rounds to 26.