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Serga [27]
3 years ago
7

The distance D that a spring is stretched by a hanging object varies directly as the weight W of the object. If a 27-kg object s

tretches a spring 53 cm, find the distance when the weight is 13-kg. Round your answer to the nearest whole centimeter.
Mathematics
2 answers:
Oxana [17]3 years ago
8 0

Answer:

The distance when the weight is 13-kg is 25.51\\ cm

Step-by-step explanation:

27\\ Kg mass of object stretches the spring by 53 \\ cm

1 \\ kg mass of object stretches the spring by \frac{53}{27} \\ cm

13 \\ kg mass of object stretches the spring by \frac{53}{27} * (13)\\= 25.51 \\ cm

yawa3891 [41]3 years ago
7 0
Cross multiply: 27x = 53*13 
x = 53*13/27 = 25.52 
Rounds to 26. 
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