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Sonja [21]
3 years ago
11

Darrien read 97 pages last week.Evan read pages last week.How many 8 my 6. pages did, the boys read?

Mathematics
1 answer:
const2013 [10]3 years ago
7 0
I’m really confused about this
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PLEASE HELP THIS IS DUE TODAY!!​
earnstyle [38]

Answer:

254 in

Step-by-step explanation:

1 yard = 36 in

7 yards = 36 (7)

7 yards = 252

add 2

254 in

:)

3 0
3 years ago
Read 2 more answers
There are 6 green marbles, 11
algol13

Step-by-step explanation:

green: 6/4

red: 7/4

this is all i know

8 0
3 years ago
See question in image and show workings​<br><br>Note : 1 nautical mile = 1.86km
ycow [4]

Answer:

a)

AB is on the latitude 30°N.

<u>Find AB:</u>

  • AB = 2*3.142*6400*cos 30°*(32+35)/360 = 6482.15 km

BC is along longitude 35°W

<u>Find BC:</u>

  • BC = 2*3.142*6400*(30 + 20)/360 = 5585.77 km

<u>Total distance traveled:</u>

  • 6482.15 + 5585.77 = 12067.92 km

<u>Convert the distance to nautical miles:</u>

12067.92/1.86 = 6488.13 nautical miles

b)

<u>Find the average speed:</u>

  • 6488.13/22 = 294.92 nautical miles / hour

<u>Note</u>. <em>This is unrealistically high speed for a ship, this must be a plane or the time given wrong.</em>

3 0
2 years ago
"You measure 34 dogs' weights, and find they have a mean weight of 67 ounces. Assume the population standard deviation is 13.5 o
liraira [26]

Answer:

The 95% confidence interval for the true population mean dog weight is between 62.46 ounces and 71.54 ounces.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96*\frac{13.5}{\sqrt{34}} = 4.54

The lower end of the interval is the sample mean subtracted by M. So it is 67 - 4.54 = 62.46 ounches.

The upper end of the interval is the sample mean added to M. So it is 67 + 4.54 = 71.54 ounces.

The 95% confidence interval for the true population mean dog weight is between 62.46 ounces and 71.54 ounces.

7 0
4 years ago
Which BEST describes the distribution of the data represented in the frequency table?
Levart [38]

Answer

yes

Step-by-step explanation:

Because yes

8 0
2 years ago
Read 2 more answers
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