Answer:
B. $275,000
Explanation:
The second machine will be depreciate over time as it can later be used for operational purposes or another research projects. The first, as can only be used for a research project It should be considered expenses for the entire amount regardless of the useful life.
Machine B useful life 10 years
depreciation expense: cost / useful life
250,000 / 10 = 25,000
machine A 250,000 + 25,000 depreciation for machine B = 275,000 total
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Answer:
$ 1,586.8743
Explanation:
Calculation to determine what will be the value of the certificate when it matures
Compounded annually
Principal P= 1000
Rate r=0.08
Period n = 6
Using this formula
A = P (1+r)^n
Let plug in the formula
1000 (1.08)^6
= 1586.8743
Therefore what will be the value of the certificate when it matures is $1586.8743
Answer:
110,000 units
Explanation:
<u>Calculation of the equivalent units of production for materials in June</u>
Beginning work in process 20,000
Units started and completed (90,000-10,000) 80,000
Ending work in process <u>10,000</u>
Equivalent units of production for materials for June <u>110,000</u> units
