Match the following items by evaluating the other expressions for x=-2 <br> HELP!

I am a 2 dimensional shape that has four sides. I have two obtuse angles and two acute angles. I have two different sets of para

OLga [1]

Answer:

Quadrilateral

Step-by-step explanation:

8 0

3 years ago

Two people start from the same point. One walks east at 4 mi/h and the other walks northeast at 8 mi/h. How fast is the distance

kvasek [131]

Answer:

5.89 mi/h

Step-by-step explanation:

This problem can be solved by using different methods. I will use vectors since it's the simplest way in which we can solve it. This can be solved by using related rates of change though.

First, we start by drawing a diagram with the velocity vectors.

A= velocity of the first person

B= velocity of the second person

C= velocity in which they are moving away from each other.

Since there is no acceleration in the problem, we can suppose we are talking about constant speeds, so the velocity at which they are moving away from each other will always remain constant. (It doesn't matter what time it is, the velocity will always be the same)

Having said this we can solve this problem by using the components, by using law of cosines or graphically. I will use law of cosines. The idea is to find the length of side c.

Law of cosines:

$C^{2}=A^{2}+B^{2}-2ABcos \gamma$

so we can solve the formula for C so we get:

$C=\sqrt{A^{2}+B^{2}-2ABcos \gamma}$

and now we can substitute the values we know:

$C=\sqrt{(4)^{2}+(8)^{2}-2(4)(8)cos 45^{o}}$

$C=\sqrt{16+64-32\sqrt{2}}$

$C=\sqrt{80-32\sqrt{2}} mph$

if we want an exact answer, then that will be the exact answer, which approximates to:

C=5.89 mph

4 0

3 years ago

How to reduce fractions

bulgar [2K]

Answer:

To simply or reduce fraction by dividing both the numerator and denominator by a number they are both divisible by.

Example:

3/12 both numbers are divisible by 3 do divide it and it becomes 1/4

6 0

3 years ago

Read 2 more answers

What are the domain and range of the inequality y < sqrt x+3+1

love history [14]

Given:

The inequality is:

$y$

To find:

The domain and range of the given inequality.

Solution:

We have,

$y$

The related equation is:

$y=\sqrt{x+3}+1$

This equation is defined if:

$x+3\geq 0$

$x\geq -3$

In the given inequality, the sign of inequality is <, it means the points on the boundary line are not included in the solution set. Thus, -3 is not included in the domain.

So, the domain of the given inequality is x>-3.

We know that,

$\sqrt{x+3}\geq 0$