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Alja [10]
3 years ago
15

Which of the following best explains why electrolyte solutions conduct electricity?

Chemistry
2 answers:
skelet666 [1.2K]3 years ago
7 0
<span>Answer: option C. the presence of free-flowing ions.
</span><span />

<span>Explanation:


Ionic compounds dissociate in water forming solutions with free ions. The solution conducts electricity and is named electrolyte.
</span><span />

<span>The ions are species with charge: cations are ions with positive charge and anions are ions with negative charge.
</span><span />

<span>The ions become the carrier of the charge so they are the responsible for the flow of current.
</span><span>
</span><span>
</span><span>So as the electrons are the carriers of the charge in the solid conductors (copper, aluminun, and others), the ions are the carriers of the charge in solutions.</span><span /><span>That is how the the electrolyte solutons conduct electricity.</span>
Irina18 [472]3 years ago
4 0

The statement that completely describes ability of electrolyte solution to conduct electricity is:

\boxed{{\text{C: the presence of free flowing ions}}}

Further explanation:

An electrolyte may be defined as the ionic compound that on dissolution in polar solvents dissociates to produce cationic and anionic species. Movement of such ionic species is responsible for the property of electrolyte to conduct electricity.

There are two kinds of electrolyte namely <em>strong electrolyte</em> and <em>weak electrolyte</em>. The strong electrolytes are those which on dissolution dissociates completely into its constituent ions however, the weak electrolytes are not completely dissociated into its constituent ions but undergo partial dissociation. Hence the strong electrolytes are better conductors of electricity as compared to weak electrolyte.

All the ionic compounds can behave as electrolytes when they are dissolved in water. In solid form, the ionic compounds cannot conduct electricity since the ions are not able to move freely however, once dissolved in aqueous solution their ions can move and produce current. For instance, the aqueous solution of sodium chloride dissociates to give sodium cation and chloride ions. The dissociation can be represented as follows:  

{\text{NaCl}}\left(s\right)\to{\text{N}}{{\text{a}}^+}\left({aq}\right)+{\text{C}}{{\text{l}}^-}\left({aq}\right)

This flow of ions and the consequent production of electric current leads to the applications in electrochemistry and synthesis of batteries and fuel cells.

Learn more:

1. Which occur during redox reaction? brainly.com/question/1616320

2. Best cleaning agent for burned-on grease: brainly.com/question/3789105

Answer details:

Grade: High school

Subject: Chemistry

Chapter: Ionic compounds

Keywords: Electrolyte, strong electrolyte, weak electrolyte, ionic compound, dissolution, cationic, anionic species, aqueous solution, solid form, current, fuel cells, electrochemistry, batteries.

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6 0
4 years ago
1) How many atoms are in 0.54 moles of Cu? show work ​
mario62 [17]
<h3>Answer:</h3>

3.3 × 10²³ atoms Cu

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Moles
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<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 0.54 moles Cu

[Solve] atoms Cu

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                      \displaystyle 0.54 \ mol \ Cu(\frac{6.022 \cdot 10^{23} \ atoms \ Cu}{1 \ mol \ Cu})
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<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

3.25188 × 10²³ atoms Cu ≈ 3.3 × 10²³ atoms Cu

7 0
3 years ago
Write the Ksp expression for the sparingly soluble compound chromium(III) hydroxide, Cr(OH)3.
Klio2033 [76]

Answer and Explanation: Ksp is the Solubility Product Constant and is the equilibrium constant that happens when a solid is dissolved in an aqueous solution.

The dissolution of chromium (III) hydroxide:

Cr(OH)_{3}_{(s)} ⇄ Cr^{3+}_{(aq)} + 3OH^{-}_{(aq0)}

Every equilibrium constant is of the form:

K = \frac{[products]^{coefficient}}{[reagents]^{coefficient}}

Then,

K_{sp} = [Cr^{3+}_{(aq)}][OH^{-}_{aq}]^{3}

The reagent is not included because solids don't take part in euqilibrium constants.

<u>So, Ksp of chromium (III) hydroxide is </u>K_{sp} = [Cr^{3+}_{(aq)}][OH^{-}_{aq}]^{3}<u />

4 0
4 years ago
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beks73 [17]

Answer:

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Explanation:

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  • Lewis structure of benzene is given below

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