Answer:
Thanks, but here is a problem I'll give myself.
Problem X+2 > 3
Step-by-step explanation:
1. Take Away 2 from both sides.
2. Answer: X > 1
The given equation is
![\frac{9}{12} = \frac{n}{32}](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B12%7D%20%3D%20%5Cfrac%7Bn%7D%7B32%7D)
Here we have to solve for n. First we need to get rid of the denominators and for that we do cross multiplication .
![9*32 = 12n](https://tex.z-dn.net/?f=9%2A32%20%3D%2012n)
Now we need to isolate n. And for that we need to get rid of 12, by dividing both sides by 12
![\frac{9*32}{12}=n](https://tex.z-dn.net/?f=%5Cfrac%7B9%2A32%7D%7B12%7D%3Dn)
![\frac{288}{12} =n](https://tex.z-dn.net/?f=%5Cfrac%7B288%7D%7B12%7D%20%3Dn)
![n=24](https://tex.z-dn.net/?f=n%3D24)
And that's the required value of n .
to graph a LINEar equation, since it's just a straight line, recall, to draw a straight line all you need is two points.
so we can just pick two random "x" values, hmmmmm say x = 0, what's "y"?
y = 7(0)-7 => y = -7....................................... so that gives us the point (0, -7)
hmmm x = 2, what is "y"?
y = 7(2) - 7 => y = 14-7 => y = 7................. so we get the point (2, 7).
then just plot those, and run a line through them.
Okay so first,
Confirm: Every time we have 7 large sugar skulls, that also makes 5 large sugar skulls. So if you have 132 <u>ALTOGETHER</u>, then you'd need to do some multiplication/division. First, divide 132 by 5, that equals 26 small sugar skulls. Lastly, 132 ÷ 7 = 18 large sugar skulls. So there are 26 small sugar skulls and 18 large sugar skulls.
(I hope that was right, I tried my best :)
Answer:
wheres the rest of the graphs?
Step-by-step explanation:
It’s NOT the first one