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Deffense [45]
3 years ago
13

Can someone please help me with this? Thank you!

Mathematics
1 answer:
kkurt [141]3 years ago
7 0

Answer:

\left[\begin{array}{ccc}-25&\dfrac{75}{2}&-\dfrac{25}{2}\end{array}\right]

Step-by-step explanation:

In the first equality

5\times \left[\begin{array}{cc}-1&2\\4&8\end{array}\right] =\dfrac{2}{5}m\times \left[\begin{array}{cc}-1&2\\4&8\end{array}\right],

the matrices in both parts are the saem. The equality will be true if the same matrices are multiplied by the same numbers, so

5=\dfrac{2}{5}m\Rightarrow m=5\times \dfrac{5}{2}=\dfrac{25}{2}

For the second equality

(H+[1\ 4\ -2])+[3\ 2\ -6]=[-2\ 3\ -1]+([1\ 4\ -2]+[3\ 2\ -6]),

if H=[-2\ 3\ -1], then this equality represents the assotiative property of matrix addition.

Hence,

m\times H=\dfrac{25}{2}\times [-2\ 3\ -1]=\left[\begin{array}{ccc}-25&\dfrac{75}{2}&-\dfrac{25}{2}\end{array}\right]

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Match each fraction with its equivalent decimal number.
Oksana_A [137]
Changing a fraction to its decimal form can be done by long division method. Dividing the denominator by its numerator will change the fraction into decimal form. Alternatively, you can use a calculator to do that for you. Below are the fractions with their decimal forms listed:

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6 0
3 years ago
At the beginning of a 10-hour experiment,a substance has an initial temperature of 19.7 degrees C. The substance is cooled at a
Olin [163]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
Suppose that at a state college, a random sample of 41 students is drawn, and each of the 41 students in the sample is asked to
ra1l [238]

Answer:

The  confidence interval for 90% confidence would be narrower than the 95% confidence

Step-by-step explanation:

From the question we are told that

  The  sample size is n = 41

   

For a 95% confidence the level of significance is  \alpha  = [100 - 95]\% =  0.05 and

the critical value  of  \frac{\alpha }{2}  is   Z_{\frac{\alpha }{2} } =Z_{\frac{0.05 }{2} }=  1.96

For a 90% confidence the level of significance is  \alpha  = [100 - 90]\% =  0.10 and

the critical value  of  \frac{\alpha }{2}  is   Z_{\frac{\alpha }{2} } =Z_{\frac{0.10 }{2} }=  1.645

So we see with decreasing confidence level the critical value  decrease

Now the margin of error is mathematically represented as

         E =  Z_{\frac{\alpha }{2} } *  \frac{s}{\sqrt{n} }

given that other values are constant and only Z_{\frac{\alpha }{2} } is varying we have that

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Hence for  reducing confidence level the margin of error will be reducing

  The  confidence interval is mathematically represented as

        \= x  - E  <  \mu <  \= x  + E

Now looking at the above formula and information that we have deduced so far we can infer that as the confidence level reduces , the critical value  reduces, the margin of error  reduces and the confidence interval becomes narrower

3 0
3 years ago
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Kisachek [45]

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So if y = |x-3| then y = 0 is the smallest output possible. We could have any positive output we want.

In terms of a graph (see below), the V shape is at the lowest point (3,0). The y coordinate is all we care about in terms of finding the range. So we see the lowest y value is y = 0.

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telo118 [61]
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4 0
3 years ago
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