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poizon [28]
3 years ago
12

What are the exponent laws

Mathematics
2 answers:
KengaRu [80]3 years ago
6 0

Answer:

Laws of Exponents. When multiplying like bases, keep the base the same and add the exponents. When raising a base with a power to another power, keep the base the same and multiply the exponents. When dividing like bases, keep the base the same and subtract the denominator exponent from the numerator exponent.

Step-by-step explanation:

Well not exactly a way to explain the answer.

Vladimir79 [104]3 years ago
5 0

Answer:

When multiplying like bases, keep the base the same and add the exponents. When raising a base with a power to another power, keep the base the same and multiply the exponents. When dividing like bases, keep the base the same and subtract the denominator exponent from the numerator exponent.

Step-by-step explanation:

Google

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Four less than twice a number is 16
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What are the coordinate of the point that is 1/5 of the way from A9-7, "-4)" to B(3, 6)? (1, 4) (-5, 0) (-5, "-2)" (0, 3)
Mkey [24]

Answer:

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Step-by-step explanation:

4 0
2 years ago
Ernie bought a new DVD that cost $12 before tax. Tax on the DVD is 8.25%. What is the total cost of the DVD including tax?
hodyreva [135]

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7 0
3 years ago
Find the mean of the data
Triss [41]
<h3>Answer:  6.282</h3>

Explanation:

Refer to the table below. I've added a third row where I multiplied each x value with its corresponding frequency value f. We can refer to this row as the xf row.

Once we know the xf values, we add them up to get 245.

We'll then divide that result over the sum of the frequency values (add everything in the second row). The sum of the frequency values is 39.

So the mean is approximately: 245/39 = 6.282051 which rounds to 6.282

Notice that this mean value is fairly close to the x value which has the highest frequency.

5 0
2 years ago
For the function given below, find a formula for the Riemann sum obtained by dividing the interval (0, 3) into n equal subinterv
Viktor [21]

Splitting up [0, 3] into n equally-spaced subintervals of length \Delta x=\frac{3-0}n = \frac3n gives the partition

\left[0, \dfrac3n\right] \cup \left[\dfrac3n, \dfrac6n\right] \cup \left[\dfrac6n, \dfrac9n\right] \cup \cdots \cup \left[\dfrac{3(n-1)}n, 3\right]

where the right endpoint of the i-th subinterval is given by the sequence

r_i = \dfrac{3i}n

for i\in\{1,2,3,\ldots,n\}.

Then the definite integral is given by the infinite Riemann sum

\displaystyle \int_0^3 2x^2 \, dx = \lim_{n\to\infty} \sum_{i=1}^n 2{r_i}^2 \Delta x \\\\ ~~~~~~~~ = \lim_{n\to\infty} \frac6n \sum_{i=1}^n \left(\frac{3i}n\right)^2 \\\\ ~~~~~~~~ = \lim_{n\to\infty} \frac{54}{n^3} \sum_{i=1}^n i^2 \\\\ ~~~~~~~~ = \lim_{n\to\infty} \frac{54}{n^3}\cdot\frac{n(n+1)(2n+1)}6 = \boxed{18}

8 0
1 year ago
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