At what point do 3x-2=26 and 5x=7y+58 intersect?

1 answer:

7 0

$3x-2=26\qquad\text{add 2 to both sides}\\\\3x=28\qquad\text{divide both sides by 3}\\\\\boxed{x=\dfrac{28}{3}}\\\\\text{Put the value of x to the second equation}\ 5x=7y+58\\\\5\left(\dfrac{28}{3}\right)=7y+58\qquad\text{multiply both sides by 3}\\\\(5)(28)=21y+174\\\\140=21y+174\qquad\text{subtract 174 from both sides}\\\\-34=21y\qquad\text{divide both sides by 21}\\\\\boxed{y=-\dfrac{34}{21}}\\\\Answer:\ \boxed{\left(\dfrac{28}{3},\ -\dfrac{34}{21}\right)}$

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Hey there :)

Let us translate each one separately
{ Using w for unknown }

The difference of a number divided by 3 and 5 is 2
'is' is the key-word, meaning you apply the = sign
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→ a number divided by 3 - 5 = 2

This is your equation:
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