Answer:
The original side length of the square was 9 ft
Step-by-step explanation:
Consider that the square was initially of side length "x" (our unknown). Then the sides were all increased by 5 ft, and now the perimeter (addition of all four sides) of the square render 56 ft.
Let's write an equation that represents the addition of the four sides of this new rectangle, and set it equal to 56 ft. Then solve for the unknown "x":

Therefore, the original side of the square was 9 ft.
Answer:
You already answered it.
Step-by-step explanation:
Answer:
y>=-3/2x-5/2
Step-by-step explanation:
-1/2y<=-3/4x+5/4
y>=-3/2x-5/2
Answer:
You must add 8 to the x and 6 to the y.
Step-by-step explanation:
(x+8,y+6)
\/
x+8 & y+6
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
Answer:
Step-by-step explanation:
13.
<h3>Given</h3>
<u>Quadratic equation</u>
- 4x² - 3x - 4 = 0
- With the roots of α and β
<h3>To Find </h3>
- The quadratic equation with roots of 1/(3α) and 1/(3β)
<h3>Solution</h3>
<u>The sum and the product of the roots of the given equation:</u>
- α + β = -b/a ⇒ α + β = -(-3)/4 = 3/4
- αβ = c/a ⇒ αβ = -4/4 = - 1
<u>New equation is:</u>
- (x - 1/(3α))(x - 1/(3β)) = 0
- x² - (1/(3α) + 1/(3αβ))x + 1/(3α3β) = 0
- x² - ((3α + 3 β)/(3α3β))x + 1/(3α3β) = 0
- x² - ((α + β)/(3αβ))x + 1/(9αβ) = 0
- x² - (3/4)/(3(-1))x + 1/(9(-1)) = 0
- x² + 1/4x - 1/9 = 0
- 36x² + 9x - 4 = 0
===================
14.
<h3>Given</h3>
<u>Quadratic equation</u>
- 3x² +2x + 7 = 0
- With the roots of α and β
<h3>To Find </h3>
- The quadratic equation with roots of α + 1/β and β + 1/α
<h3>Solution</h3>
<u>The sum and the product of the roots of the given equation:</u>
- α + β = -b/a ⇒ α + β = -2/3
- αβ = c/a ⇒ αβ = 7/3
<u>New equation is:</u>
- (x - (α + 1/β))(x - (β + 1/α)) = 0
- x² - (α + 1/β + β + 1/α)x + (α + 1/β) (β + 1/α) = 0
- x² - (α + β + (α + β)/αβ )x + αβ + 1/αβ + 2 = 0
- x² - (-2/3 - (2/3)/(7/3))x + 7/3 + 1/(7/3) + 2 = 0
- x² - (-2/3 - 2/7)x + 7/3 + 3/7 + 2 = 0
- x² + (14 + 6)/21x + (49 + 9 + 42/21) = 0
- x² + 20/21x + 100/21 = 0
- 21x² + 20x + 100 = 0