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liubo4ka [24]
3 years ago
8

How do you expand (x-10)(x-10)​

Mathematics
1 answer:
denpristay [2]3 years ago
4 0
1 Answer
1.multiply the First terms. x⋅x=x2.
2.multiply the Outside terms. x⋅10=10x.
3.multiply the Inside terms. −10⋅x=−10x.
4.multiply the Last terms. −10⋅10=−100.
5.add all of the answers together. x2+10x−10x−100.
6.combine like terms. x2+10x−10x−100. =x2−100.
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Write an equation with a slope of -1/2 in each form.<br> point-slope form<br> slope-intercept form.
Evgen [1.6K]

For the case of a line through

(

2

,

7

)

and

(

1

,

−

4

)

we have

slope

m

=

Δ

y

Δ

x

=

−

4

−

7

1

−

2

=

−

11

−

1

=

11

Using the point

(

2

,

7

)

we can write the equation of the line in point slope form as:

y

−

7

=

m

(

x

−

2

)

where the slope

m

=

11

.

That is:

y

−

7

=

11

(

x

−

2

)

To get point intercept form, first expand the right hand side so...

y

−

7

=

11

x

−

(

11

⋅

2

)

=

11

x

−

22

Then add

7

to both sides to get:

y

=

11

x

−

15

=

11

x

+

(

−

15

)

This is point intercept (

y

=

m

x

+

c

) form with slope

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=

11

and intercept

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=

−

15

.

6 0
3 years ago
HELP asap<br> the pic saids it all
alisha [4.7K]
Second one tell me if im wrong
4 0
3 years ago
Read 2 more answers
Researchers recorded the speed of ants on trails in their natural environments. The ants studied, Leptogenys processionalis, all
posledela

This question is Incomplete

Complete Question

Researchers recorded the speed of ants on trails in their natural environments. The ants studied, Leptogenys processionalis, all have the same body size in their adult phase, which made it easy to measure speeds in units of body lengths per second (bl/s). The researchers found that, when traffic is light and not congested, ant speeds vary roughly Normally, with mean 6.20 bl/s and standard deviation 1.58 bl/s. (a) What is the probability that an ant's speed in light traffic is faster than 5 bl/s? You may find Table B useful. (Enter your answer rounded to four decimal places.)

Answer:

0.7762

Step-by-step explanation:

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score

μ is the population mean

σ is the population standard deviation.

Population mean = 6.20 bl/s

Standard deviation = 1.58 bl/s.

x = 5 bl/s

z = 5 - 6.20/1.58

z = -0.75949

The probability that an ant's speed in light traffic is faster than 5 bl/s is P( x > 5)

Probability value from Z-Table:

P(x<5) = 0.22378

P(x>5) = 1 - P(x<5)

= 1 - 22378

= 0.77622

Approximately to 4 decimal places = 0.7762

The probability that an ant's speed in light traffic is faster than 5 bl/s is 0.7762

5 0
3 years ago
What is the area?
balu736 [363]

Answer:

Solution given:

For rectangle

length [L]=BC=16in

breadth [b]=AB=4in

For traingle

length[l]=8in

breadth [b]=3in

total area =area of rectangle ABCD+2×area of triangle DEF

=L×b+2×1/2×[b×h]

=16×4+8×3=88in² is your answer

4 0
3 years ago
What is the following sum 3b^2
densk [106]

The given expression is 3b^2*(\sqrt[3]{54a}) + 3*(\sqrt[3]{2ab^6})

This can be simplified as :

= 3*b^2*(\sqrt[3]{27 *2*a}) + 3*(\sqrt[3]{2*a*b^6})

We know that: \sqrt[3]{27}  = 3

Similarly we also can simplify: \sqrt[3]{b^6}  = b^2

So our expression will look like this:

= 3*3*b^2*(\sqrt[3]{2a}) + 3*b^2*(\sqrt[3]{2a})

= 9b^2*(\sqrt[3]{2a}) + 3b^2*(\sqrt[3]{2a})

=\sqrt[3]{2a}*(9b^2 + 3b^2)

=\sqrt[3]{2a}*(12b^2)

This can also be written as:

12b^2(\sqrt[3]{2a})

So the Answer is Option B


6 0
3 years ago
Read 2 more answers
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