Answer:
Step-by-step explanation:
1/5 + 1/5 = 2/5
1/7 + 1/7 = 2/7
1/3 + 1/3 = 2/3
There are an infinite number of these fractions. They must be 1 and 1 in the numerator, and the denominator must be relatively prime to 2. The examples I have picked are prime in the denominator, but the rule is not without many exceptions. For example
1/9 + 1/9 = 2/9
I don't think you can pick an even denominator because it will reduce when put with two. Oh wait 2/18 + 2/18 = 4/18 = 2/9 But these could be reduced before adding. Still, it might count. It depends on who is marking the question.
What about an odd and even denominator?
1/9 + 1/18 = 3/18 = 1/6 There must be something that works, but I can't come up with an example.
It should be 324. 9+9=18 18^2=324
We are given the function f(x) = x + 5 in which the abscissa chosen is at x = 4w. To find the ordinate or the y-component, we replace x with 4w in the equation given. In this case, y = 4w + 5. Hence the answer to this problem is B. (4w, 4w + 5)
X=12
if you us the Pythagorean theorem, (a^2+b^2=c^2), plug the numbers in, you can work backwards and find the answer.