A. Area of ABCD - Area of DGA = Area of DEFG
s^2 - 1/2bh = s^2
(5)^2 - 1/2(4)(3) = (3)^2
25 - 1/2(12) = 9
25 - 24 = 9
1 not equal to 9
B. Area of ABCD - Area of GHIA = Area of DGA
s^2 - s^2 = 1/2bh
(5)^2 - (4)^2 = 1/2(4)(3)
25 - 16 = 1/2(12)
9 not equal to 6
C. Area of ABCD + Area of DGA = Area of GHIA
s^2 + 1/2bh = s^2
(5)^2 + 1/2(4)(3) = (4)^2
25 + 1/2(12) = 16
25 + 6 = 16
31 not equal to 16
D. Area of DEFG + Area of GHIA = Area of ABCD
s^2 + s^2 = s^2
(3)^2 + (4)^2 = (5)^2
9 + 16 = 25
25 = 25
The answer is D.
Answer:
64
Step-by-step explanation:
A square has equal side measurements meaning that each side is 8. To find the area, multiply the length by the width which would be 8 * 8 = 64.
Answer:
He needs 3 cups of sugar, so he should use 1 cup less
Step-by-step explanation:
Answer
Find out the percentage of students from the north side of the city in the program .
To prove
Formula

As given
A magnet school program was set up to bring in students from all over the city. With the first 112 students .
the magnet program had 50% from the south side of town, 12.5% from the north side l, and 37.5% from the east side.
12 .5 % is written in the decimal form.

= 0.125
North side student be = 0.125 × 112
= 14
As given
If 6 more student from the north side and 2 students from the west side side enrolled in the program .
than north side student becomes = 14 + 6
= 20
Total number of student becomes = 112 + 6 + 2
= 120
put in the above formula


= 16.66% (approx)
Therefore 16.66% (approx) students from the north side of the city in the program .