Landsteiner Bertillon devised a technique for determining the blood group of a dried bloodstain, which he applied to criminal investigations.
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What about blood group?</h3>
- According to the presence or absence of antibodies and hereditary antigenic compounds on the surface of red blood cells, blood is classified according to its type.
- Depending on the blood group system, these antigens could be proteins, carbohydrates, glycoproteins, or glycolipids.
- The genes that a person got from their parents determine what blood type they have.
- There are numerous systems for classifying blood types, but ABO is the most popular one.
- The ABO group is divided into four main categories: A, B, O, and AB.
- There are eight more blood types within these groupings.
- Each of the eight blood types has a particular ability to save lives.
- The majority of people (37% of the population) have the blood type O+, which is the most prevalent. This indicates that there is a greater need for this blood type for blood transfusions.
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Answer:
They remain in an environment,even as more competitive species arrive
Explanation:
Pioneer species, in ecological succession, are the first set of organisms to colonize a bare area of land or a disturbed area of land. Pioneer species include lichens, grasses, fungi etc.
Pioneer species have unique characteristics that distinguishes them from every other species of organism. These include:
- They facilitate environmental change, making an environment more habitable for other species.
- They tolerate a wide range of environmental conditions.
- They are capable of colonizing a barren environment, as in primary succession.
However, pioneer species do not remain in an environment, even as more competitive species arrive. They rather give way for new species to emerge and dominate.
Answer:
Explanation:
To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.
The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.
So, en the exposed example:
- J and K are autosomal genes
- J and K are separated by 60 M.U.
- 60 M.U. means that there is 60% of recombination.
Cross) J K / j k x j k / j k
Gametes) JK Parental jk, jk, jk, jk
jk Parental
Jk Recombinant
jK Recombinant
One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.
1 M.U. -------------- 1% recombination
60 M.U. ------------ 60% recombination
30% Jk + 30% jK
100 M.U. - 60 M.U. = 40 M.U.
40M.U.--------------40 % Parental (Not recombinant)
20% JK + 20% jk
Punnet Square) JK jk Jk jK
jk JK/jk jk/jk Jk/jk jK/jk
J K / j k = 20%
j k / j k = 20%
J k / j k = 30%
j K / j k = 30%
Answer:
the genetic code is universal.
Explanation:
