"1 indicating a coupon and all other outcomes indicating no coupon"
Probability is (number of successful outcomes) / (number of possible outcomes)
Theoretical Probability of rolling a 1: 1/8
Experimental Probability of using coupons: 4/48 = 1/12
So, the experimental probability of a customer using a coupon (that is, 1/12) is smaller than the theoretical probability of rolling a 1 (that is, 1/8).
Small number =X
mid number = 3X-4
large number = 3x
X+3X-4+3X=24
7X-4=24
7X-4+4=24+4
7X=28
X=28/7
X=4
S=4
M=3(4) -4=12-4=8
L=3(4)=12
The numbers are 4,8 and 12
1. d
x-intercept (y=0) is -4
y-intercept (x=0) is 8
2. d
x-intercept (y=0) is 16
y-intercept (x=0) is 20
3. b
y=1/6x+4
multiplied by 6
6y=x+24
-x+6y=24
4. a 4.75k+2.25p=22
Answer: it is dilation
Step-by-step explanation: i took the exam