Answer: No, the side lengths of 5, 5 and 10 would not be able to.
So the answer is FALSE.
This is because all the lengths must be enough so that when you add the side lengths they are greater then the other, all would work accept 5+5 is not greater than 10.
The length of the fencing is 62.4 feet.
The width of the fencing is 17.6 feet.
Given,
The measurement of the Christmas garland = 160 feet
The width of the fencing = w
The length of the fencing, l = 4w - 8
We have to find the length and width of the fencing.
Here,
Perimeter can be taken as 160. Because garland will cover the entire fencing.
Perimeter = 2(l + w)
160 = 2(4w - 8 + w)
160 = 2(5w - 8)
160/2 = 5w - 8
80 + 8 = 5w
88/5 = w
width = 17.6 feet
Now,
l = 4w - 8
l = 4 × 17.6 - 8
l = 70.4 - 8
length = 62.4 feet
That is,
The length of the fencing is 62.4 feet.
The width of the fencing is 17.6 feet.
Learn more about perimeter here:
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30 + 70 + D = 180
100 + D = 180
D = 80°
Answer:
A: the graph will cross the x-axis