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Marysya12 [62]
3 years ago
8

The sum of three numbers is 24. the largest number is three times the smallest, and the middle number is four less than the larg

est. what are the numbers
Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
6 0
Small number =X
mid number = 3X-4
large number = 3x

X+3X-4+3X=24
7X-4=24
7X-4+4=24+4
7X=28
X=28/7
X=4

S=4
M=3(4) -4=12-4=8
L=3(4)=12

The numbers are 4,8 and 12
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A roller coaster has four cars each with the same number of seats. these are 21 passengers seated in the roller coaster, but 3 s
belka [17]

Given:

Number of passengers seated in the roller coaster = 21

Empty seats = 3

Number of cars in roller coaster = 4 (each with the same number of seats)

To find:

An equation that can be used to determine the number of seats in each car.

Solution:

Let s be the number of seats in each car.

Total number of seats in 4 cars = 4s

Using the given information,

Total number of seats = Occupied seated + Empty seats

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                                   = 24

Now, the required equation is

4s=24

Therefore, the required equation is 4s=24.

Divide both sides by 4.

s=\dfrac{24}{4}

s=6

Therefore, the number of seats in each car is 6.

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A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a
zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}

Hence the answer is 0.1157

(ii) None is defective becomes

\begin{gathered} \lparen\frac{5}{6})^4=\frac{625}{1296} \\ =0.4823 \end{gathered}

hence the answer is 0.4823

(iii) All are defective

\begin{gathered} \lparen\frac{1}{6})^4=\frac{1}{1296} \\ =0.00077 \end{gathered}

(iv) At least one is defective

This is 1 - probability that none is defective

\begin{gathered} 1-\lparen\frac{5}{6})^4 \\ =1-\frac{625}{1296} \\ =\frac{671}{1296} \\ =0.5177 \end{gathered}

Hence the answer is 0.5177

3 0
10 months ago
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