Answer:
Step-by-step explanation:
Given
Probability of clearing exam in 1 st attempt=0.5
Probability of clearing exam in 2 nd attempt=0.7
Probability of clearing exam in 3 rd attempt=0.8
Probability that she passes the exam
(b)P(Pass qualification on 2nd try|passes qualification)
P(Pass qualification on 2nd try|passes qualification)
P(Pass qualification on 2nd try|passes qualification)
Answer:
False
Step-by-step explanation:
<u>According to the complex conjugate root theorem:</u>
if a complex number is a root of a polynomial, its conjugate is also the root of the polynomial
We are given all the roots of the polynomial and there is only one complex root
Since according to the complex conjugate root theorem, there can be either none or at least 2 complex roots of a polynomial
We can say that this set of roots of a polynomial is incorrect
Answer:
The inequality which represents the graph is y ≤ -2x + 1 ⇒ A
Step-by-step explanation:
To solve the question you must know some facts about inequalities
- If the sign of inequality is ≥ or ≤, then it represents graphically by a solid line
- If the sign of inequality is > or <, then it represents graphically by a dashed line
- If the sign of inequality is > or ≥, then the area of the solutions should be over the line
- If the sign of inequality is < or ≤, then the area of the solutions should be below the line
Let us study the graph and find the correct answer
∵ The line represented the inequality is solid
∴ The sign of inequality is ≥ or ≤
→ That means the answer is A or B
∵ The shaded area is the area of the solutions of the inequality
∵ The shaded area is below the line
∴ The sign of inequality must be ≤
→ That means the correct answer is A
∴ The inequality which represents the graph is y ≤ -2x + 1
Answer:
In First method : counting up, counting back on a number line,
If we want the quotient after dividing the number by 5 then we count how many 5 we get from 0 to the dividend.
For example : 
Since, from 0 to 30 there are six 5's obtained. ( because 5 × 6 = 30 )
Thus, 
In Second Method : dividing by 10, and then doubling the quotient.
First we divide the number by 10 then multiply the quotient by 2.
For Example:
Since, 
Thus,
Now, when we compare the above methods then we conclude that for the smaller numbers first method is appropriate because for small numbers we can easily count total 5's from 0. While for large numbers Second method is appropriate because it is hard to count the total 5's for the large number.
