Answer:
b
Step-by-step explanation:
Using the trigonometric identities
cot x = 
and tan x = 
thus
+ tanΘ × cosΘ
= 
+ 
× cosΘ
= cosΘ × + sinΘ
= sinΘ + sinΘ
= 2sinΘ → b
Answer:
Step-by-step explanation:
We look for where 
. The way you find the answer is first, find the point 
. Draw a line straight up and down, and see where that line intersects the function. Those intersection points are your answer(there will always be only 1 for a function, but if a graph isn't a function, there might be more than 1).
Using this method here, we see that 
intersects our line at 
, so .
Answer:
Step-by-step explanation:
Subtract 9 from both sides:
Add 6x to both sides:
Divide both sides by -4:
Assuming the equation is x^2 + y^2 = 1, then that's a circle, with radius 1, centered on the origin [0,0].
So there are two tangents at x = 0. They are y = 1, and y = -1 (horizontal lines).
There is one tangent at x = 1. It is x = 1 (a vertical line).
There is no tangent at x = 35, because the original equation has no solution at x = 35.
