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2 years ago

Help me asappppp please

Mathematics

1 answer:

katen-ka-za [31]2 years ago

6 0

Answer:

lol wow you dont know that lololololololololol

Step-by-step explanation:

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Two bicyclists were racing toward each other when they were 98 miles apart. Three hours later they did not meet yet and the dist

lesya [120]

Let, speed of 1st bicyclist is x.

So, speed of 2nd bicyclist is x-3 .

We know, relative speed when two objects moves towards each other :

$v = x + ( x-3 )\\\\v = 2x - 3$

Now, distance travelled in 3 hours is (98-2) miles .

So,

$2x-3 = \dfrac{96}{3}\\\\2x - 3 = 32\\\\2x = 35\\\\x = 17.5\ mph$

Therefore, speed of bikes are 17.5 mph and 14.5 mph.

Hence, this is the required solution.

5 0

2 years ago

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo

muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: $P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}$

Where $\lambda$ is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

$P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}$

Substitute the respective values in the above formula.

$P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})$

$P(k > 2)= 1 - (0.44596)$

$P(k > 2)=0.55404$

Hence, the required probability is 0.55404.

4 0

2 years ago

Algebra 2 help plsass

Novosadov [1.4K]

Answer:

Step-by-step explanation:

6 0

2 years ago

You decide to take your car on a drive through Canada, where gas is sold in liters and distances are measured in kilometers. Sup

12345 [234]

Answer:

the no of liters required is 50.55 liters

Step-by-step explanation:

Given that

The car gas efficiency is 23.0 mi/gal

distance is 495 km

1 gal = 3.78 L

1 km = 0.6214 mi

We need to find out the no of liters of gas that would needed to complete a trip

So,

= (495 × 3.78 × 0.6214) ÷ (23)

= 50.55 Liters

hence, the no of liters required is 50.55 liters

7 0

2 years ago

The two triangles illustrated below are similar. What are the values of x and y?

poizon [28]

Answer:

${ \bf{by \: relations : }} \\ { \tt{ \frac{28}{7} = \frac{x}{8} }} \\ \\ { \tt{x = \frac{28 \times 8}{7} }} \\ x = 32 \\ \\ { \tt{y = 83 \degree}}$

5 0

2 years ago