Question

Factoring math/////////

Answer 1

Answer:

Step-by-step explanation:

If you want to factor this, you have to use the quadratic formula to do so.

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

For us, it looks like this:

$x=\frac{-3+/-\sqrt{(-3)^2-4(5)(4)} }{2(5)}$

which simplifies to

$x=\frac{-3+/-\sqrt{-71} }{10}$

Since it breaks every mathematical rule to have a negative number under an even index radical, we have to deal with that using the imaginary "i".  You should know at this point that $i^2=-1$

so we will do a rewrite on that equation above:

$x=\frac{-3+/-\sqrt{i^2*71} }{10}$

which simplifies further to

$x=\frac{-3+/-i\sqrt{71} }{10}$

This is the answer but we can separate it into its proper standard form which is

$x=-\frac{3}{10}+\frac{\sqrt{71} }{10}i$ and $x=-\frac{3}{10}-\frac{\sqrt{71} }{10}i$

Answer 2

Answer:

Step-by-step explanation:

If you want to factor this, you have to use the quadratic formula to do so.

For us, it looks like this:

which simplifies to

Since it breaks every mathematical rule to have a negative number under an even index radical, we have to deal with that using the imaginary "i".  You should know at this point that

so we will do a rewrite on that equation above:

which simplifies further to

This is the answer but we can separate it into its proper standard form which is

and

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