algebra, is a type of math.
PART A:
Find the rate of change between 1980 and 1989
d for P₁ = 80 - 60
d for P₁ = 20
d for P₂ = 76 - 82
d for P₂ = -6
The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.
PART B:
Find the rate of change between 1989 and 1996
d for P₁ = 100 - 80
d for P₁ = 20
d for P₂ = 70 - 76
d for P₂ = -6
The rate of change in P₁ is 20 hundred per year. The rate of change in P₂ is -6 hundred per year.
PART C:
Find the rate of change between 1980 and 1996
d for P₁ = 100 - 60
d for P₁ = 40
d for P₂ = 70 - 82
d for P₂ = -12
The rate of change in P₁ is 40 hundred per year. The rate of change in P₂ is -12 hundred per year.
Answer:
C. 
Step-by-step explanation:
I think the equation meant
?
Anyways, to factor these kinds of quadratic, keep into consideration:

ONLY if:

Start off by finding factors of c, which in this case, -18:
±(1, 2, 3, 6, 9, 18)
If one of the numbers is negative then the other number must be positive.
Find which two factors will sum up to b, which in this case, is 3.

The only two factors that work are 6 and -3.
Replace them into the factored form:

1 jar=26 fluid ounces( converted it to cups)which is 3.25 cups.
To find 4 jars, just multiply 3.25 and 4 to get 13.