Answer:
1.92 yd x 3.83 yd x 2.58 yd
Step-by-step explanation:
We have given a rectangular base, that its twice as long as it is wide.
It must hold 19 yd³ of debris.
Lets minimize the surface area, subject to the restriction of volume (19 yd³)
The surface is given by:
The volume restriction is:
replacing h in the surface equation, we have:
Derivate the above equation and set it to zero
![dS/dw=57(-1)w^{-2} + 8w=0\\\\57w^{-2}=8w\\\\w^3=57/8=7.125\\\\w=\sqrt[3]{7.124} =1.92](https://tex.z-dn.net/?f=dS%2Fdw%3D57%28-1%29w%5E%7B-2%7D%20%2B%208w%3D0%5C%5C%5C%5C57w%5E%7B-2%7D%3D8w%5C%5C%5C%5Cw%5E3%3D57%2F8%3D7.125%5C%5C%5C%5Cw%3D%5Csqrt%5B3%5D%7B7.124%7D%20%3D1.92)
The height will be:
Therefore,The dimensions that minimize the surface are:
Wide: 1.92 yd
Long: 3.83 yd
Height: 2.58 yd
Answer:
214.5 seconds or less time will qualify individuals for such training
Step-by-step explanation:
given that the time that it takes a randomly selected job applicant to perform a certain task has a distribution that can be approximated by a normal distribution with a mean value of 150 sec and a standard deviation of 25 sec.
i.e. X the time that it takes a randomly selected job applicant to perform a certain task is N(150,25)
The fastest 10% are the ones who are above the 90th percentile
We know 90th percentile for Z std normal score is 1.28
Corresponding X score would be
Round off to one decimal
214.5 seconds or less time will qualify individuals for such training
Answer:
910 mL = 0.91 L
9.1 L = 9,100 mL
0.901 kL = 901 L
91 L = 0.091 kL
90.1 L = 90,100 mL
9,010 mL = 9.01 L
Step-by-step explanation:
A=18
Explanation:multiply both sides by 3 to get rid of the fraction so u are left with a=18
