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AveGali [126]
2 years ago
12

If f(1) =5 and f(n) = f(n-1)+2, then f(4) =

Mathematics
1 answer:
Vadim26 [7]2 years ago
5 0

Answer:

3.11

Step-by-step explanation:

f(4)=f(4-1)+2

=f(3)+2

=f(3-1)+2+2

=f(2)+4

=f(2-1)+2+4

=f(1)+6

=5+6 (f(1)=5)

=11

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Consider the set T = {1, 2, 3, 4, 5, 6}. Let R = {(a, b) | a divides b} be a relation on the set T. Identify the missing ordered
serg [7]

Answer:  The missing ordered pairs are  (2, 2), (2, 4), (2, 6), (3, 3) and (3, 6).

Step-by-step explanation:  We are given the following set :

T = {1, 2, 3, 4, 5, 6}.

And, R = {(a, b) | a divides b} be a relation on the set T.

We are to identify the missing pairs from the following list of all ordered pairs in the given relation R on the set T :

{(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), _____, (4, 4), (5, 5), and (6, 6).}.

Since R contains the ordered pairs (a, b) such that a divides b, so all the ordered pairs in R are

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 2), (2, 4), (2, 6), (3, 3), (3, 6), (4, 4), (5, 5), and (6, 6).

Thus, the missing ordered pairs are  (2, 2), (2, 4), (2, 6), (3, 3) and (3, 6).

4 0
3 years ago
Which is the best estimate for the mass of a pair of eyeglasses? A. 25 grams B. 250 grams C. 25 kilograms D. 250 kilograms
Yuliya22 [10]
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4 0
3 years ago
Please help me now ! Thank you
jarptica [38.1K]
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now

2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4

At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real. 

Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result. 

For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196

No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.

So x^2 = -4 has no real solutions. Taking the square root of both sides leads to

x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values


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Answer:

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What's the name of the line segment in the diagram below? A. B. C. D.
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