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3 years ago

5

In order for the table below to show exponential decay, what must the value of d be in the table below?

2 answers:

Eduardwww [97]3 years ago

9 0

Let x represent the domain
Let y represent the range.

Assume that y =a*b⁻ˣ

Set x=0:
a*b⁰ = 32
a = 32

Set x=1:
32*b⁻¹ = 24
32 = 24b
b = 32/24

Set x=2:
d = 32*(32/24)⁻²
= 32*(24/32)²
= (32*24*24)/(32*32) = 24²/32 = 576/32
= 18

Answer: 18

BARSIC [14]3 years ago

6 0

Answer: 18

Step-by-step explanation:

Because Igot it right on my test

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2 years ago

If g(x) = 2 − 1, what is g(−2.3)?

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3 years ago

Read 2 more answers

1.Given the function h(t) = t³ - 2t, find h(-5).

Svetllana [295]

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-65

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2 years ago

) Find the coordinates of the point A' which is the symmetric point

soldier1979 [14.2K]

Let, coordinate of point A' is (x,y).

Since, A' is the symmetric point A(3, 2) with respect to the line 2x + y - 12 = 0.

So, slope of line containing A and A' will be perpendicular to the line 2x + y - 12 = 0 and also their center lies in the line too.

Now, their center is given by :

$C( \dfrac{x+3}{2}, \dfrac{y+2}{2})$

Also, product of slope will be -1 .( Since, they are parallel )

$\dfrac{y-2}{x-3} \times -2 = -1\\\\2y - 4 = x - 3\\\\2y - x = 1$

x = 2y - 1

So, $C( \dfrac{2y -1 +3}{2}, \dfrac{y+2}{2})\\\\C( \dfrac{2y + 2}{2}, \dfrac{y+2}{2})$

Also, C satisfy given line :

$2\times ( \dfrac{2y + 2}{2}) + \dfrac{y+2}{2} = 12\\\\4y + 4 + y + 2 = 24\\\\5y = 18\\\\y = \dfrac{18}{5}$

Also,

$x = 2\times \dfrac{18}{5 } - 1\\\\x = \dfrac{31}{5}$

Therefore, the symmetric points is $A'(\dfrac{31}{5}, \dfrac{18}{5})$ .

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2 years ago