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3 years ago

Write the equation of the line that passes through the points (-4,8) and (1,3)

Mathematics

1 answer:

Ksju [112]3 years ago

7 0

Answer:

y = -x+4; Use the slope formula (y2-y1/x2-x1) and work backwards using that formula.

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Find f(4) please, I need help

mixer [17]

Answer:

f(4) = 1

Step-by-step explanation:

f(4) = what?

So if we know that x, aka 4, is technicially f is greater then 2, so you can plug in x as 4. So that means 5(4) - 19 = 20 - 19 = 1, so f(4) = 1

7 0

2 years ago

What is the value of m in the equation 5m − 7 = 6m + 11? A.18 B. 1 C. −18 D.−1

adoni [48]

Hello there ^ _ ^

5m - 7 = 6m + 11
Solve for M
5m - 6m = 11+ 7
-m = 18
Divide both sides by -1
-m/-1 = 18/-1
m = -18

Good luck!

6 0

3 years ago

Read 2 more answers

What's the slope of -4,6 and 3,-8

notsponge [240]

Answer:

The slope is -2

Step-by-step explanation:

(-4,6) (3,-8)

(y₂ - y₁) / (x₂ - x₁)

((-8) - (6)) / ((3) - (-4))

(-8 - 6) / (3 + 4)

-14/7 = -2

4 0

3 years ago

The frequency distributions of two data sets are shown in the dot plots below.

fredd [130]

Answer:

1st, 4th and 6th statements are true.

Step-by-step explanation:

We have been given two dot-plots and we are asked to select all the true statements about given dot plots.

Let us write all the data points of both dot plots.

Data set 1:

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 7.

Data set 2:

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4.

1. The mean of data set 1 is greater than the mean of data set 2.

Let us find mean of both data sets.

$\text{Mean of data set 1}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4+7}{19}$

$\text{Mean of data set 1}=\frac{45}{19}$

$\text{Mean of data set 1}=2.3684\approx 2.37$

$\text{Mean of data set 2}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4}{18}$

$\text{Mean of data set 2}=\frac{38}{18}$

$\text{Mean of data set 2}=2.11$

We can see that mean of data set 1 is greater than mean of data set 2, therefore, 1st statement is true.

2. The mean of data set 1 is equal to the mean of data set 2.

Since mean of data set 1 is greater than mean of data set 2, therefore, 2nd statement is false.

3. The median of data set 1 is greater than the median of data set 2.

Since data set 1 has 19 data points, so median of data set 1 will be value of 10th data set, that is 2.

Our data set 2 has 18 data points, so median of data set 2 will be the average of 9th and 10th data points.

$\text{Median of data set 2}=\frac{2+2}{2}$

$\text{Median of data set 2}=\frac{4}{2}=2$

Since median of data set 2 is also 2, therefore, 3rd statement is not true.

4. The median of data set 1 is equal to the median of data set 2.

Since both data set's median is 2, therefore, 4th statement is true.

5. The standard deviation of data set 1 is smaller than the standard deviation of data set 2.

Using online SD calculator we get SD of data set 1 is 1.422 and SD of data set 2 is 0.936. Since 1.422 is greater than 0.936, therefore, 5th statement is false.

6. The data sets have the same interquartile range.

$Q_1\text{ of data set 1}=1$

$Q_3\text{ of data set 1}=3$

$\text{IQR of data set 1}=3-1=2$

$Q_1\text{ of data set 2}=1$

$Q_3\text{ of data set 2}=3$

$\text{IQR of data set 2}=3-1=2$

Since both data set's IQR is 2, therefore, 6th statement is true.

3 0

3 years ago

Read 2 more answers

Help please!!! Pre-calculus

Anvisha [2.4K]

Answer:

P ( 3, - pi/3 + 2 pi n) or P ( -3 , -pi/3 + pi(2 n +1))

Step-by-step explanation:

P ( 3, - pi/3)

We can circle 2pi n around the circle and be back at the same polar coordinate

P ( 3, - pi/3 + 2 pi n)

or we can flip the radius to a negative and add pi to the theta

P ( -3, - pi/3 + pi)

Then we can circle 2pi n around the circle and be back at the same polar coordinate

P ( -3 , -pi/3 + 2 pi n +pi)

P ( -3 , -pi/3 + pi(2 n +1))

6 0

3 years ago