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Ronch [10]
3 years ago
15

Please help me with this

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
5 0
Adjacent angles are angles that share a common side as if they were morphed together.
Complementary angles are angles that sum up to be 90°

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Mr. Salvi makes car payments of $489.95 each month.
SIZIF [17.4K]

Answer:

$5879.4

Step-by-step explanation:

the monthly expense of the car is $489.95

no. of months=12

therefore, the expense= 489.95×12

=$5879.4

6 0
3 years ago
jessica will babysit children for $8 an hour. ciara will babysit for an appointment fee of $12 and $4 an hour. how many hours wo
SSSSS [86.1K]

Answer:

Answer are in bold below

Step-by-step explanation:

Question: 1

Jessica = $8

Ciara = $12 + 4 $16

Now we times both values.

16 x 8 = $128

8 x 16 = $128

They would both need to work 8 hours ft=or the same money.

Question 2:

$8 x 5 = $40

$16 x 5 =$80

Jessica will be less expensive.

5 0
3 years ago
Read 2 more answers
Can you help me find the missing value to the nearest hundredth?! <br>cos□= 2/5 <br><br>Thank you ❤
Aleksandr [31]

Answer:

66.42°

Step-by-step explanation:

Given

cos ? = \frac{2}{5} , then

? = cos^{-1} (\frac{2}{5} ) ≈ 66.42° ( to the nearest hundredth )

7 0
3 years ago
Colin has a pad with x pieces of paper on it. For his first class, he wrote on 5 fewer than half of the pieces of paper in the p
PIT_PIT [208]

Answer:

Colin has <em>8 sheets </em>left for his third class.

Step-by-step explanation:

Given that:

Total Number of pieces of papers = x

Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad

Writing the equation:

\text{Number of pieces of papers used for 1st class =} \dfrac{x}{2} -5 ...... (1)

Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.

\text{Number of pieces of papers used for 2nd class =} \dfrac{x}{2} -5+2 = \dfrac{x}2 -3 ...... (2)

Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class

\text{number of pieces of papers left for the third class = }x-(\dfrac{x}{2}-5)-(\dfrac{x}{2}-3)\\\Rightarrow x-\dfrac{x}2-\dfrac{x}2+5+3\\\Rightarrow x-x+5+3\\\Rightarrow 8

So, the answer is:

Colin has <em>8</em> <em>sheets </em>left for his third class.

5 0
3 years ago
Find the value of the variable in each expression
bogdanovich [222]

Answer:

they're all 0

Step-by-step explanation:

N/A

6 0
2 years ago
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