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Ronch [10]
3 years ago
15

Please help me with this

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
5 0
Adjacent angles are angles that share a common side as if they were morphed together.
Complementary angles are angles that sum up to be 90°

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A number is equal to twice a smaller number plus 3. The same number is equal to twice the sum of the smaller number and 1. How m
Orlov [11]

Answer: No solutions exist because the situation describes two lines that have the same slope and different y-intercepts.

7 0
3 years ago
What is f(5) if f(1)= 3.2 and f(x+1)=5/2(f(x))
Yanka [14]
F(2) = (5/2)f(1) = 8.0
f(3) = (5/2)f(2) = 20
f(4) = (5/2)f(3) = 50
f(5) = (5/2)*50 = 125
7 0
3 years ago
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6th grade math help me, please:))
Leokris [45]

Answer:

40 percent

Step-by-step explanation:

(10/25 ) x 100 = (2/5) x100 = (0.4) x 100 = 40% of the roses was given away.

7 0
3 years ago
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Find the solutions to the equation<br><br> -3y(2y+5)=0
noname [10]

Answer:

The solutions are y=0, -5/2

Step-by-step explanation:

-3y(2y+5)=0

We can use the zero product property

-3y =0  2y+5 =0

y =0     2y = -5

             y = -5/2

The solutions are y=0, -5/2

3 0
3 years ago
7+3√5/3+√5 - 7-3√5/3-√5 = a + b√5
daser333 [38]
<h3>Given:-</h3>

\\ \sf \implies\frac{7 + 3 \sqrt{5} }{3 +  \sqrt{5} }  -  \frac{7  - 3 \sqrt{5} }{3  -   \sqrt{5} }  = a +  \sqrt{5} b \\

<h3>To Find:-</h3>

  • The value of a and b

<h3>Solution:-</h3>

\\ \sf \implies\frac{7 + 3 \sqrt{5} }{3 +  \sqrt{5} }  -  \frac{7  - 3 \sqrt{5} }{3  -   \sqrt{5} }  = a +  \sqrt{5} b \\

\\ \sf \implies\frac{( \: 7 + 3 \sqrt{5} \:  \: (  3  -   \sqrt{5}) \:  \:  - 7  -  3 \sqrt{5} \:  \: (  3   +    \sqrt{5}) \: }{(3 +  \sqrt{5})  \:  \:(3 +  \sqrt{5}) }   = a +  \sqrt{5}  \:  b\\

\\ \sf \implies\frac{( \: 21 - 7 \sqrt{5} \:   +  9    \sqrt{5} - 15) \:  \:  - ( \: 21  + 7 \sqrt{5} \:    -  9    \sqrt{5}  +  15)\: }{(3 +  \sqrt{5})  \:  \:(3 +  \sqrt{5}) }   = a +  \sqrt{5}  \:  b\\

\\ \sf \implies\frac{( \: 6 + 2 \sqrt{5} ) \:  \:  - ( \: 6 - 2 \sqrt{5} )\: }{(3 +  \sqrt{5})  \:  \:(3 +  \sqrt{5}) }   = a +  \sqrt{5}  \:  b\\

\\ \sf \implies\frac{\: 6 + 2 \sqrt{5}  \:  \:  -  \: \: 6 - 2 \sqrt{5} \: }{(3 +  \sqrt{5})  \:  \:(3 +  \sqrt{5}) }   = a +  \sqrt{5}  \:  b\\

\\ \sf \implies\frac{\: 4 \sqrt{5}  \:  \:   }{3  {}^{2}   -  {\sqrt{5} }^{2}  }   = a +  \sqrt{5}  \:  b\\

\\ \sf \implies\frac{\: 4 \sqrt{5}  \:  \:   }{ \:  \:  \:  \: 9 - 5 \:  \:  \:   }   = a +  \sqrt{5}  \:  b\\

\\ \sf \implies\frac{\: 4 \sqrt{5}  \:  \:   }{ \:  \:  \:  \: 4 \:  \:  \:   }   = a +  \sqrt{5}  \:  b\\

\\ \sf \implies\frac{\: \cancel{4 } \sqrt{5}  \:  \:   }{ \:  \:  \:  \:  \cancel{4 }\:  \:  \:   }   = a +  \sqrt{5}  \:  b\\

\\ \sf \implies \: \sqrt{5}  = a +  \sqrt{5}  \:  b\\

we can also write it as ;

\\ \sf \implies \: 0 + \sqrt{5}  = a +  \sqrt{5}  \:  b\\

★<u> </u><u>Henceforth, the value of a and b are</u> :

→ a = 0

→ b = 1

6 0
2 years ago
Read 2 more answers
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