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3 years ago

Please help me with this

Mathematics

1 answer:

d1i1m1o1n [39]3 years ago

5 0

Adjacent angles are angles that share a common side as if they were morphed together.
Complementary angles are angles that sum up to be 90°

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The lengths of three

True [87]

Answer:

90 cm, 180 cm, 240 cm

Step-by-step explanation:

Let the lengths of sides of the triangle be 3x, 6x and 8x

$\therefore \: 3x + 6x + 8x = 5.1 \: m \\ \therefore \: 17x = 510 \: cm \\ \therefore \: x = \frac{510}{17} \\ \therefore \:x = 30 \: cm \\ \implies \\ 3x = 3 \times 30 = 90 \: cm \\ 6x = 6 \times 30 = 180 \: cm \\ 8x = 8 \times 30 = 240 \: cm$

Hence, lengths of the sides of the triangle are 90 cm, 180 cm and 240 cm.

4 0

3 years ago

A store had 913 sodas, both diet and regular. The ratio of diet sodas to regular sodas was 8:3. How many diet sodas were there?

Elodia [21]

Answer:

<h2>There are 664 diet soda</h2>

Step-by-step explanation:

Step one:

given data

total soda= 913

we are told that the ratio of diet sodas to regular sodas is 8:3

this means that for every 8 diet soda there is 3 regular soda

the total ratio is 8+3=11

Step two:

we are going to use part to all principle

let the diet soda be x

8/11=x/913

cross multiply

11x=913*8

divide both sides by 11

x=913*8/11

x=7304/11

x=664

There are 664 diet soda

5 0

3 years ago

Solve for 3(x+1) = 2(x-1)<br> Somebody PLEASE HELP!!

beks73 [17]

Answer:use the app socratic

Step-by-step explanation:for all math answers

8 0

3 years ago

Read 2 more answers

Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

1 year ago

Write an equivalent logarithmic equation.<br><br> e^x = 30

saul85 [17]

E^x=30
the logarithmic equation: ⇒ ln 30=x

4 0

4 years ago