<h3>(-3j²k³)²(2j²k)³</h3>
(-3j²k³)²(2j²k)³ = <em>When a power is raised to a power the exponents have to be multiplied.</em>
= (-3²j⁽²*²⁾k⁽³*²⁾)(2³j⁽²*³⁾k³) = <em>We can take out the constants</em>
= (9)(8)(j⁴k⁶)(j⁶k³) = <em>We can group the same variables</em>
= 72(j⁴j⁶)(k⁶k³) = <em>When multiplying two powers that have the same base, you have to add the exponents.</em>
= 72 j⁽⁴⁺⁶⁾k⁽⁶⁺³⁾ = 72j¹⁰k⁹
Answer = 72j¹⁰k⁹
Hope this helps!
The answers would be 11, if you plug it in it would be 5(11)-7=48
Answer:
yes
Step-by-step explanation:
Answer:
35-7-7-7-7-7=0 also 35-7=28-7=21-7=14-7=7-7=0
Step-by-step explanation:
48-12-12-12-12=0 also 48-12=36-12=24-12=12-12=0
72-8-8-8-8-8-8-8-8-8=0 also 72-8=64-8=56-8=48-8=40-8=32-8=24-8=16-8=8-8=0
Answer:
(16, 11) or ( 16, 10 )
Step-by-step explanation: