Answer:
x=30
Step-by-step explanation:
3(x+2)^3/5 +3=27
Subtract 3 from each side
3(x+2)^3/5 +3-3=27-3
3(x+2)^3/5 =24
Divide by 3
3/3(x+2)^3/5 =24/3
(x+2)^3/5 =8
Take everything to the 5/3 power to get rid of the exponent on the left side
(x+2)^3/5 ^ 5/3=8 ^ 5/3
Remember that a^b^c = a^ (b*c)
(x+2)^(3/5 * 5/3)=8 ^ 5/3
(x+2)=8 ^ 5/3
Replace 8 with 2^3
(x+2)=2^3 ^ 5/3
Remember that a^b^c = a^ (b*c)
(x+2)=2^(3 * 5/3)
x+2 = 2^5
x+2 = 32
Subtract 2 from each side
x+2-2 = 32-2
x=30
Let 
be the amount of food needed for one man for one day. At the beginning, we have enough food for 400 men for 40 days, i.e.
After 10 days, the 400 men will have consumed
food, impliying that the food remaining is
If 200 more men join the garrison, there are now 600 men. Each of them requires food each day, and there are 
units of food remaining. They will last
days.
Answer:
Step-by-step explanation:
3c + 2e = 6.10
e = c + 0.30
3c + 2(c + 0.30) = 6.10
5c + 0.60 = 6.10
5c = 5.50
c = 1.10 Є
e = c + 0.30 = 1.40 Є
Given a triangle ABC below
To find the value of m∠A, we use the cosine formula which is
Where
Substitute the values into the cosine formula above
Hence, m∠A is 75.3° (one decimal place)
