B. Venus hope this helps have a great day
I hope that helps you!!!!!!
<h3>
Answer:</h3>
539.56 Joules
<h3>
Explanation:</h3>
- Efficiency of a machine is the ratio of work output to work input expressed as a percentage.
- Efficiency = (work output/work input) × 100%
- Efficiency of a machine is not 100% because so energy is lost due to friction of the moving parts and also as heat.
In this case;
Efficiency = 94%
Work input = 574 Joules
Therefore, Assuming work output is x
94% = (x/574 J) × 100%
0.94 = (x/574 J)
<h3>x = 539.56 J</h3>
Thus, you get work of 539.56 J from the machine
Answer:
a. 2.856 x 10^-6 m³
b. 0.288 J
c. 971.88 J
d. 971.592 J
Explanation:
d) The change in internal energy of the cube.
Note: For Copper -
B(beta)= 5.1 × 10^-3 (C)^-1
Cp = 390J/Kg.K
p (Rho) = 8.90 × 10³Kg/m³
Detailed solution is attached below
