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3 years ago

In the sentence Argon has several properties distinct from other gases", what does distinct mean?

Physics

1 answer:

svlad2 [7]3 years ago

8 0

Answer:

Distinct means separate.

Option: C

Explanation:

From the given sentence Argon has several properties that are separate from other gases. This sentence refers that Argon gas has many properties that are different from other gases.

The things are distinct from one another, they are different. Although, the solubility of oxygen is same as Argon. Argon is soluble in water in the form of nitrogen. This gas is isolated through the liquid air fractionation only 0.94% argon is present in the atmosphere.

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Starting at its rightmost position, it takes 2 seconds for the pendulum of a grandfather clock to swing a horizontal distance of

sdas [7]

Answer:

The correct answer is b, x = 9 cos (pi / 2 t)

Explanation:

The equation that describes a simple pendulum is

θ = θ₀ cos (wt + φ)

The angle is measured is radians

θ = x / L

We replace

d / L = x₀ / L cos (wt + φ)

x₀ = 9 in

We replace

d = 9 cos (wt + φ)

Angular velocity is related to frequency and period.

w = 2π f = 2π / T

The period is the time of a complete oscillation T = 4 s

w =2π / 4

w = π / 2

Let's replace

x = 9 cos (π/2 t + φ)

As the system is released from the root x = x₀ for t = 0 s

x₀ = x₀ cos φ

Cos φ = 1

φ = 0°

The final equation is

x = 9 cos (pi / 2 t)

The correct answer is b

8 0

3 years ago

Read 2 more answers

The order of elements in the periodic table is based on the atomic number. true or false

kirill [66]

True the elements are ordered in the atomic number

4 0

3 years ago

A man-made satellite of mass 6105 kg is in orbit around the earth, making one revolution in 430 minutes. What is the magnitude o

blondinia [14]

Answer:

A gravitational force of 6841.905 newtons is exerted on the satellite by the Earth.

Explanation:

At first we assume that Earth is represented by an uniform sphere, such that the man-made satellite rotates in a circular orbit around the planet. Hence, the following condition must be satisfied:

$\left(\frac{4\pi^{2}}{T^{2}} \right)\cdot r = \frac{G\cdot M}{r^{2}}$ (1)

Where:

$T$ - Period of rotation of the satellite, measured in seconds.

$r$ - Distance of the satellite with respect to the center of the planet, measured in meters.

$G$ - Gravitational constant, measured in newton-square meters per square kilogram.

$M$ - Mass of the Earth, measured in kilograms.

Now we clear the distance of the satellite with respect to the center of the planet:

$r^{3} = \frac{G\cdot M\cdot T^{2}}{4\pi^{2}}$

$r = \sqrt[3]{\frac{G\cdot M\cdot T^{2}}{4\pi^{2}} }$ (2)

If we know that $G = 6.67\times 10^{-11}\,\frac{N\cdot m^{2}}{kg^{2}}$ , $M = 6.0\times 10^{24}\,kg$ and $T = 25800\,s$ , then the distance of the satellite is:

$r = \sqrt[3]{\frac{\left(6.67\times 10^{-11}\,\frac{N\cdot m^{2}}{kg^{2}} \right)\cdot (6.0\times 10^{24}\,kg)\cdot (25800\,s)^{2}}{4\pi^{2}} }$

$r \approx 18.897\times 10^{6}\,m$

The gravitational force exerted on the satellite by the Earth is determined by the Newton's Law of Gravitation:

$F = \frac{G\cdot m\cdot M}{r^{2}}$ (3)

Where:

$m$ - Mass of the satellite, measured in kilograms.

$F$ - Force exerted on the satellite by the Earth, measured in newtons.

If we know that $G = 6.67\times 10^{-11}\,\frac{N\cdot m^{2}}{kg^{2}}$ , $M = 6.0\times 10^{24}\,kg$ , $m = 6105\,kg$ and $r \approx 18.897\times 10^{6}\,m$ , then the gravitational force is: