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AnnyKZ [126]
3 years ago
15

Which of the following is a vector quantity?

Physics
2 answers:
lutik1710 [3]3 years ago
6 0

Since vectors are essentially quantities that have direction, D must be the answer as it contains a direction (down) while the other ones do not.

otez555 [7]3 years ago
3 0

A vector is a quantity with a size and a direction.

The only choice that has both of those is D .

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A ___________ spreads from one machine to another rapidly without human action
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Answer: Worm

A virus spreads from one machine to another rapidly without human action. A virus is like a code that runes automatically without any knowledge or without taking permission of the user. It hampers the way a machine works. When a machine is attached to another machine directly or indirectly containing virus, it spreads itself. A worm is a kind of virus  that can spread with zero human intervention. A virus still requires a human to download a contaminated file but worm does not. a worm can spread on its own

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Here's a tip: The unit of frequency ... Hertz or Hz ... means "per second". "Five times PER SECOND" is a frequency of 5 Hz.
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A glass falls off a shelf. How fast is the glass moving after 0.4 seconds?
tresset_1 [31]

On Earth, gravity increases the speed of a falling object by about 9.8 m/s
every second that it falls.

In 0.4 second, its speed increases by (0.4 x 9.8) = 3.92 m/s.

If it just rolled off of the shelf at the beginning of that 0.4 second, then it
started from zero speed, and its speed after 0.4 second is 3.92 m/s.

Its velocity is 3.92 m/s downward.


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3 years ago
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A sphere moves in simple harmonic motion with a frequency of 4.80 Hz and an amplitude of 3.40 cm. (a) Through what total distanc
geniusboy [140]

Answer:

a)  the total distance traveled by the sphere during one cycle of its motion = 13.60 cm

b) The maximum speed is = 102.54 cm/s

The maximum speed occurs at maximum excursion from equilibrium.

c)  The maximum magnitude of the acceleration of the sphere is = 30.93 m/s^2

The maximum acceleration occurs at maximum excursion from equilibrium.

Explanation:

Given that :

Frequency (f) = 4.80 Hz

Amplitude (A) = 3.40 cm

a)

The total distance traveled by the sphere during one cycle of simple harmonic motion is:

d = 4A   (where A is the Amplitude)

d = 4(3.40 cm)

d = 13.60 cm

Hence, the total distance traveled by the sphere during one cycle of its motion = 13.60 cm

b)

As we all know that:

x = Asin \omega t

Differentiating the above expression with respect to x ; we have :

\frac{d}{dt}(x) = \frac{d}{dt}(Asin \omega t)

v = A \omega cos \omega t

Assuming the maximum value of the speed(v) takes place when cosine function is maximum and the maximum value for cosine function is 1 ;

Then:

v_{max} = A \omega

We can then say that the maximum speed therefore occurs at the mean (excursion) position where ; x = 0  i.e at maximum excursion from equilibrium

substituting 2 \pi f for \omega in the above expression;

v_{max} = A(2 \pi f)

v_{max} = 3.40 cm (2 \pi *4.80)

v_{max} = 102.54 \ cm/s

Therefore, the maximum speed is = 102.54 cm/s

The maximum speed occurs at maximum excursion from equilibrium.

c) Again;

v = A \omega cos \omega t

By differentiation with respect to  t;

\frac{d}{dt}(v) = \frac{d}{dt}(A \omega cos \omega t)

a =- A \omega^2 sin \omega t

The maximum acceleration of the sphere is;

a_{max} =A \omega^2

where;

w = 2 \pi f

a_{max} = A(2 \pi f)^2

where A= 3.40 cm = 0.034 m

a_{max} = 0.034*(2 \pi *4.80)^2

a_{max} = 30.93 \ m/s^2

The maximum magnitude of the acceleration of the sphere is = 30.93 m/s^2

The maximum acceleration occurs at maximum excursion from equilibrium where the oscillating sphere will have maximum acceleration at the turning points when the sphere has maximum displacement of x  = \pm A

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Answer:

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