Answer:
1 and 4, 2 and 3, 5 and 8, 6 and 7
Step-by-step explanation:
Step-by-step explanation:
8²+x²=17²
74+ײ=289
x²=225
Sq root both sides
x=15
15×8=120 Sq ft
The expected length of code for one encoded symbol is

where
is the probability of picking the letter
, and
is the length of code needed to encode
.
is given to us, and we have

so that we expect a contribution of

bits to the code per encoded letter. For a string of length
, we would then expect
.
By definition of variance, we have
![\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3DE%5Cleft%5B%28L-E%5BL%5D%29%5E2%5Cright%5D%3DE%5BL%5E2%5D-E%5BL%5D%5E2)
For a string consisting of one letter, we have

so that the variance for the length such a string is

"squared" bits per encoded letter. For a string of length
, we would get
.
Answer:
-1772
Step-by-step explanation:
The nth term of an arithmetic sequence is expressed as;
Tn = a+(n-1)d
a is the first term
n is the number of terms
d is the common difference
From the sequence
a = 28
d = 8-28 = -12-8 = -20
n =91(since we are looking for the 91st term)
Substrate
T91 = 28+(91-1)(-20)
T91 = 28+90(-20)
T91 = 28-1800
T91 = -1772
Hence the 91st term is -1772
The given details follow the product rule. The different model of the car available are 756.
Given that:




The different possibility is calculated using the following product rule:

So, we have:


Hence, there are 756 different models available.
Read more about product rules at:
brainly.com/question/3944602