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Elza [17]
2 years ago
15

NEED HELP ASAP............... proofs

Mathematics
1 answer:
Kaylis [27]2 years ago
5 0

Answer:

h

Step-by-step explanation:

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Hi! im not sure if my answer is correct or not can someone check me :)
Maslowich
It is correct goodluck
7 0
2 years ago
Which expression is equivalent to x y Superscript two-ninths?
crimeas [40]

Option D: x\sqrt[9]{y^2} is the expression equivalent to xy^{\frac{2}{9}}

Explanation:

Option A: \sqrt{xy^9}

The expression can be written as ({xy^9})^{\frac{1}{2}

Applying exponent rule, we get,

x^{\frac{1}{2}} y^{\frac{9}{2}}

Thus, the expression \sqrt{xy^9} is not equivalent to the expression xy^{\frac{2}{9}}

Hence, Option A is not the correct answer.

Option B: \sqrt[9]{xy^2}

The expression can be written as ({xy^2})^{\frac{1}{9}

Applying exponent rule, we get,

x^{\frac{1}{9}} y^{\frac{2}{9}}

Thus, the expression \sqrt[9]{xy^2} is not equivalent to the expression xy^{\frac{2}{9}}

Hence, Option B is not the correct answer.

Option C: x\sqrt{y^9}

The expression can be written as x(y^9)^{\frac{1}{2} }

Applying exponent rule, we get,

x y^{\frac{9}{2}}

Thus, the expression x\sqrt{y^9} is not equivalent to the expression xy^{\frac{2}{9}}

Hence, Option C is not the correct answer.

Option D: x\sqrt[9]{y^{2} }

The expression can be written as x(y^2)^{\frac{1}{9} }

Applying exponent rule, we get,

xy^{\frac{2}{9}}

Thus, the expression xy^{\frac{2}{9}} is equivalent to the expression xy^{\frac{2}{9}}

Hence, Option D is the correct answer.

4 0
3 years ago
Read 2 more answers
A NASA spacecraft measures the rate R of at which atmospheric pressure on Mars decreases with altitude. The result at a certain
AysviL [449]

Answer:

R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}

Step-by-step explanation:

For this case we have the following value:

R = 0.0498 \frac{Kpa}{Km}

We can convert this first to \frac{Kpa}{m} like this:

R=0.0498 \frac{Kpa}{Km} *\frac{1km}{1000m}=0.0000498 \frac{Kpa}{m}

Now we use the fact the the pressure is defined as P =\frac{F}{A}, whre P is the pressure, F the force and A the area, so then Kpa= \frac{KN}{m^2} and then we can replace this:

R=0.0000498 \frac{KN}{m^3}

Now from definition of work we know that W= Fd where W is the work, F the force and d the distance, so then is equivalent KN =\frac{KJ}{m}

And if we replace this into the equation we got:

R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}

4 0
3 years ago
Arthur made the Scatterplot below of the temperature outside his house over the course of nine days at the begging of winter if
Oksi-84 [34.3K]
20 degrees.  The pics a little blurry, but it should be that
7 0
3 years ago
Can somebody check my answer please <br> I think the answer is 56 but I want to be sure :)
leva [86]

Answer:

yup its right

Step-by-step explanation:

7uhkt8kfd

8 0
2 years ago
Read 2 more answers
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