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3 years ago

NEED HELP ASAP............... proofs

Mathematics

1 answer:

Kaylis [27]3 years ago

5 0

Answer:

Step-by-step explanation:

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Evaluate 0.1m+8-12n0.1m+8−12n0, point, 1, m, plus, 8, minus, 12, n when m=30m=30m, equals, 30 and n=\dfrac14n= 4 1 n, equals,

Rom4ik [11]

Answer:

Step-by-step explanation:

We are required to evaluate:

0.1m+8-12n

When $m=30, n=\frac{1}{4}$

Substituting these values into the expression, we have:

$0.1m+8-12n=0.1(30)+8-12(\frac{1}{4})\\=3+8-\frac{12}{4}\\=3+8-3\\=8$

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3 years ago

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What is the answer to 3c=-21?

Anna71 [15]

First, you need to get the variable by itself.
Divide three by both side.
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3 years ago

Which symbol correctly compares the two fractions?

dedylja [7]

Answer:

5/12<3/6

Step-by-step explanation:

3/6 is 1/2 and 5/12 is smaller than 1/2

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3 years ago

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A metallurgist has one alloy containing 34% copper another containing 48% copper. How many pounds of each alloy must he use to m

Zielflug [23.3K]

Answer:

<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>

Step-by-step explanation:

First alloy contains 34% copper and the second alloy contains 48% alloy.

We wish to make 46 pounds of a third alloy containing 37% copper.

Let the weight of first alloy used be $x$ in pounds and the weight of second alloy used be $y$ in pounds.

Total weight = $46\text{ }pounds=x+y$ $-(i)$

Total weight of copper = $37\%\text{ of 46 pounds = }34\%\text{ of }x\text{ pounds + }48\%\text{ of }y\text{ pounds }$

$\dfrac{37\times 46}{100}=\dfrac{34x}{100}+\dfrac{48y}{100}\\\\ 34x+48y=1702$ $-(ii)$

Subtracting 34 times first equation from second equation,

$34x+48y-34x-34y=1702-34\times46\\14y=138\\y=9.857\text{ }pounds \\x=36.143\text{ }pounds$

∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.

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3 years ago

Hello please help thanks

ikadub [295]

Answer:

most likely the last choice

Step-by-step explanation:

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