1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
klemol [59]
3 years ago
15

"matrix multiplication" please respond to the following: determine whether or not matrix multiplication is commutative. support

your answer using at least one (1) real-world example of scenario.
Mathematics
1 answer:
jeka943 years ago
3 0

Answer:

Matrix multiplication is not commutative.

Step-by-step explanation:

Matrix multiplication is not commutative which means that the result of A*B is not equal to the result of B*A which suggests that the order does matter in matrix multiplication.

AB ≠ BA

Real-world Example:

We can model a set of equations that will represent the number of games  won by each team.

Let x represents team Brazil and y represents team Spain.

2x + 3y = 12

6x + 8y = 34

In the matrix form

\left[\begin{array}{ccc}2&3\\6&8\\\end{array}\right]   \left[\begin{array}{ccc}x\\y\\\end{array}\right]   = \left[\begin{array}{ccc}12\\34\\\end{array}\right]

When we solve this matrix we get x = 3 and and y = 2

Which means that Brazil has won 3 games and Spain has won 2 games.

Now if you change the order of these variables then you wont get the correct results and this is exactly why matrix multiplication is not commutative because the order is important in matrix multiplication.

You might be interested in
Squered root of 72 in simplest radical form ?
serious [3.7K]
2/72 = 36
2/36 = 18
2/18 = 9
3/9 = 3
3/3 = 1

so now as you can see we have 3 number which is divided by 2 and 2 numbers which is divided by 3. so it becomes, 3*2√2 = 6√2 is final answer. 
7 0
3 years ago
Write an expression to show .... Five times the difference of 17 and 8
UkoKoshka [18]

Answer:

5(17-8)

Step-by-step explanation:

5(17-8)

5(9)

=45

4 0
3 years ago
Read 2 more answers
Is 1/x^4 in simplest form
madam [21]

Answer:

Yes. It is the simplest form as it cannot be simplified by any variables or values.

4 0
3 years ago
QUESTION ON PIC THANK YOU !!!
AlexFokin [52]
Triangle a - acute
Triangle b - acute
Triangle c - acute
Triangle d - right
8 0
2 years ago
Read 2 more answers
WILL MARK BRAINLIEST!!! 40 POINTS!! ACTUAL ANSWERS, PLZZZ
steposvetlana [31]

Answer:

Part A:

\left(x + 7\right)^{5}=x^{5} + 35 x^{4} + 490 x^{3} + 3430 x^{2} + 12005 x + 16807

Part B:

The closure property describes cases when mathematical operations are CLOSED. It means that if you apply certain mathematical operations in a polynomial it will still be a polynomial. Polynomials are closed for sum, subtraction, and multiplication.

It means:

\text{Sum of polynomials } \Rightarrow \text{ It will always be a polynomial}  

\text{Subtraction of polynomials } \Rightarrow \text{ It will always be a polynomial}  

\text{Multiplication of polynomials } \Rightarrow \text{ It will always be a polynomial}  

But when it is about division:

\text{Division of polynomials } \Rightarrow \text{ It will not always/sometimes be a polynomial}  

<u>Example of subtraction of polynomials:</u>

<u />(2x^2+2x+3) - (x^2+5x+2)<u />

<u />x^2-3x+1<u />

Step-by-step explanation:

<u>First, it is very important to define what is a polynomial in standard form: </u>

It is when the terms are ordered from the highest degree to the lowest degree.

Therefore I can give:

x^5-5x^4+3x^3-3x^2+7x+20

but,

x^5+3x^3-3x^2+7x+20-5x^4 is not in standard form.

For this question, I can simply give the answer: x^5-5x^4+3x^3-3x^2+7x+20 and it is correct.

But I will create a fifth-degree polynomial using this formula

$(a+b)^n=\sum_{k=0}^n \binom{n}{k} a^{n-k} b^k$

Also, note that

$\binom{n}{k}=\frac{n!}{(n-k)!k!}$

For a=x \text{ and } b=7

$\left(x + 7\right)^{5}=\sum_{k=0}^{5} \binom{5}{k} \left(x\right)^{5-k} \left(7\right)^k$

\text{Solving for } k \text{ values: } 0, 1, 2, 3, 4 \text{ and } 5

Sorry but I will not type every step for each value of k

The first one is enough.

For k=0

$\binom{5}{0} \left(x\right)^{5-0} \left(7\right)^{0}=\frac{5!}{(5-0)! 0!}\left(x\right)^{5} \left(7\right)^{0}=\frac{5!}{5!} \cdot x^5= x^{5}$

Doing that for k values:

\left(x + 7\right)^{5}=x^{5} + 35 x^{4} + 490 x^{3} + 3430 x^{2} + 12005 x + 16807

8 0
3 years ago
Other questions:
  • The local music activities coordinator sold 300 tickets to the orchestra concert. Student tickets were $4, and adult tickets wer
    11·1 answer
  • Your parents allow you to borrow a car to get to your part-time job, but you have to pay for a tank of gas each month. Gasoline
    14·1 answer
  • What is 4(x2 – 3x) + 12x2 + x simplified?<br> F 4x2–3x H 16x2–11x G13x2–2x I16x2–12x
    10·1 answer
  • Whoever asnwers first and gets the answer right will get brainliest.
    10·2 answers
  • I will give you 100 points and brainliest if you answer
    11·2 answers
  • Rani had Rs800 left after spending 75% of her money.How much money did she have in the beginning?
    13·1 answer
  • Factor this expression using the GCF (greatest common factor) and then explain how you can verify your answer:
    12·1 answer
  • PLEASE HELP!
    15·1 answer
  • Helpppppppppppppppppppppppp
    9·2 answers
  • . A parcel delivery service lowered its A parcel delivery service lowered its prices and finds that it has delivered twice as ma
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!