X3(2x2 + 3x) a. 2x5 + 3x4 b. 5x9 c. 2x6 + 3x3 d. 5x

Mathematics

1 answer:

Serhud [2]3 years ago

5 0

Answer:

$2x^5+3x^4$

Step-by-step explanation:

$x^3\left(2x^2+3x\right)$

<u>Apply distributive law: </u> $a\left(b+c\right)=ab+ac$

$x^3\left(2x^2+3x\right)=x^3\times \:2x^2+x^3\times \:3x$

$x^3\times \:2x^2+x^3\times \:3x$

$2x^5+3x^4$

<u>OAmalOHopeO</u>

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$\huge\fbox{Answer ☘}$

$\bold{3( \frac{27}{8} ) {}^{ \frac{2}{3} \times - 1} = 2( \frac{32}{243} ) {}^{2x} }\\ \\3(( \frac{3}{2} ) {}^{3} ) {}^{ \frac{2}{3} \times - 1 } = 2(( \frac{2}{3} ) {}^{5} ) {}^{2x} \\\\ 3( \frac{3}{2} ) {}^{2 \times - 1} = 2( \frac{2}{3} ) {}^{10x} \\\\ 3( \frac{2}{3} ) {}^{2} = 2( \frac{2}{3} ) {}^{10x} \\\\ 3( \frac{4}{9} ) = 2( \frac{4}{9} ) {}^{5x} \\\\\bold\pink{ comparing \: powers }\\\\5x = 1 \\\\ \bold\blue{x = \frac{1}{5} }$