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andreyandreev [35.5K]
3 years ago
12

From a group of six people, two individuals are to be selected at random. how many possible selections are there

Mathematics
1 answer:
Murrr4er [49]3 years ago
6 0
You can do C(6,2) which gives 6*5/2 which is 15!
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Find the nth term:
san4es73 [151]

Answer:

n+3

Step-by-step explanation:

the relationship between those numbers are consistently adding 3 thus n +3

7 0
3 years ago
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Convert 1 cal/(m^2 * sec * °C) into BTU/(ft^2 * hr * °F)
Crazy boy [7]

Answer:

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Step-by-step explanation:

To find : Convert 1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C} into \frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Solution :

We convert units one by one,

1\text{ m}^2=10.7639\text{ ft}^2

1\text{ sec}=\frac{1}{3600}\text{ hour}

1\text{ cal}=0.003968\text{ BTU}

Converting temperature unit,

^\circ C\times \frac{9}{5}+32=^\circ F

1^\circ C\times \frac{9}{5}+32=33.8^\circ F

So, 1^\circ C=33.8^\circ F

Substitute all the values in the unit conversion,

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{0.101061}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

Therefore, The conversion of unit is 1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}

3 0
3 years ago
HELP! I put the formula but I don’t know the radius
ahrayia [7]

Answer:

C. 8,624

Step-by-step explanation:

recall that the formula for circumference is

Circumference = 2πr  ( = given as 85 meters)

hence,

85 = 2πr

r = 85/(2π)

given h = 15m

volume of cylinder

= πr²h

= π (85/2π)² 15  (using calculator and assuming π = 3.14)

= 8628.58

Comparing with the choices, the closest choice (within rounding error) is C. 8,624

8 0
3 years ago
Lines e and f are parallel. The mAngle9 = 80° and mAngle5 = 55°. Parallel lines e and f are cut by transversal c and d. All angl
brilliants [131]

Answer:

(A)m\angle 2=125^\circ\\(C)m\angle 8=55^\circ\\(E)m\angle 14=100^\circ

Step-by-step explanation:

The diagram of the problem is drawn and attached.

Given that:

m\angle 9 =80^\circ\\m\angle 5 =55^\circ

m\angle 5+ m\angle 6=180^\circ\\55^\circ+ m\angle 6=180^\circ\\m\angle 6=180^\circ-55^\circ\\m\angle 6=125^\circ\\$Now:\\m\angle 6 = m\angle 2 $(Corresponging angles)\\Therefore m\angle 2=125^\circ\\

m\angle 5= m\angle 8=55^\circ $(Vertically Opposite Angles)

Also

m\angle 9+ m\angle 10=180^\circ\\80^\circ+ m\angle 10=180^\circ\\m\angle 10=180^\circ-80^\circ\\m\angle 10=100^\circ\\$Now:\\m\angle 10 = m\angle 14 $(Corresponging angles)\\Therefore m\angle 14=100^\circ\\

4 0
3 years ago
Read 2 more answers
Trying to figure this out
prisoha [69]
I hope this helps you

6 0
3 years ago
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