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Marina86 [1]
4 years ago
14

What is the slope of the line that passes through the pair of points?

Mathematics
2 answers:
shepuryov [24]4 years ago
8 0

Answer:

The correct answer is option A.

Step-by-step explanation:

Two points are given :(x_1,y_1)(x_2,y_2):(-5.5, 6.1), (-2.5, 3.1)

Slope from the two point is determined by the formula :

slope=\frac{y_2-y_1}{x_2-x_1}

slope=\frac{3.1-(6.1)}{(-2.5)-(-5.5)}=\frac{3.0}{-3.0}=-1

The slope of the line that passes through the pair of points is -1.

Hence, the correct answer is option A.

Mazyrski [523]4 years ago
4 0
I think the answer is going to be a
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3 years ago
Given the vectors A⃗ and B⃗ shown in the figure ((Figure 1) ), determine the magnitude of B⃗ −A⃗. A is 28 degrees above the posi
Vlad [161]

This problem is represented in the Figure below. So, we can find the components of each vector as follows:


\bullet \ cos(28^{\circ})=\frac{Adjacent}{Hypotenuse}=\frac{A_{x}}{44} \\ \\ \therefore A_{x}=44cos(28^{\circ})=38.85m \\ \\ \\ \bullet \ sin(28^{\circ})=\frac{Opposite}{Hypotenuse}=\frac{A_{y}}{44} \\ \\ \therefore A_{y}=44sin(28^{\circ})=20.65m


\bullet \ cos(56^{\circ})=\frac{Adjacent}{Hypotenuse}=\frac{-B_{x}}{26.5} \\ \\ \therefore B_{x}=-26.5cos(56^{\circ})=-14.81m \\ \\ \\ \bullet \ sin(56^{\circ})=\frac{Opposite}{Hypotenuse}=\frac{B_{y}}{26.5} \\ \\ \therefore B_{y}=26.5sin(56^{\circ})=21.97m


Therefore:

\vec{A}=(38.85, 20.65)m \\ \\ \vec{B}=(-14.81, 21.97)m


So:

\vec{B}-\vec{A}=(-14.81, 21.97)-(38.85, 20.65)=(-53.66,1.32)


Finally, the magnitude is:


\boxed{\left| \vec{B}-\vec{A}\right|=\sqrt{(-53.66)^2+(1.32)^2}=53.67m}

7 0
3 years ago
Read 2 more answers
Evaluate g(p)•h(p) by modeling or by using the distribution property
Nataly [62]

g(p) \cdot h(p) = p^{4}+2 p^{3}-8 p^{2}-2p+4

Solution:

Given data:

g(p)=(p-2) and h(p)=\left(p^{3}+4 p^{2}-2\right)

To find g(p) \cdot h(p):

g(p) \cdot h(p)= (p-2)\cdot \left(p^{3}+4 p^{2}-2\right)

Distributive property: a(b+c)=ab + ac

               = p\left(p^{3}+4 p^{2}-2\right) -2\left(p^{3}+4 p^{2}-2\right)

               = \left(p^{4}+4 p^{3}-2p\right) +\left(-2p^{3}-8 p^{2}+4\right)

               = p^{4}+4 p^{3}-2p-2p^{3}-8 p^{2}+4

Arrange and add/subtract same powers.

              = p^{4}+(4 p^{3}-2p^{3})-8 p^{2}-2p+4

               = p^{4}+2 p^{3}-8 p^{2}-2p+4

Hence g(p) \cdot h(p) = p^{4}+2 p^{3}-8 p^{2}-2p+4

5 0
3 years ago
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