Regular heptagonSolve for <span>area
</span>A= 7/4 x a^2 x cot(180 degrees/7)
https://www.google.com/search?sourceid=chrome-psyapi2&rlz=1C1ZQQI_enUS697US697&ion=1&espv=2&ie=UTF-8&q=area%20of%20a%20heptagon%20formula&oq=area%20of%20a%20heptagon&aqs=chrome.1.69i57j0l5.4065j0j7
https://www.google.com/search?sourceid=chrome-psyapi2&rlz=1C1ZQQI_enUS697US697&ion=1&espv=2&ie=UTF-8<span>&q=area%20of%20a%20heptagon%20formula&oq=area%20of%20a%20heptagon&aqs=chrome.1.69i57j0l5.4065j0j7</span>
37/100 as a decimal<span> equals </span><span>0.37.</span>
f= <span><span>−<span>0.764706s</span></span>+22.294118</span>
<span>f= <span>25.321429</span></span>
Answer:
Angle of A = 90 degree-62 degree = 28 degree.
Step-by-step explanation:
tan (62) = opposite / adjacent = 10 / a ---> a = 10/tan (62) = 10/ 1.88 = 5.319
cos (62) = a/c --->c = a/cos (62) = 5.319 / 0.47 = 5.3 / 0.47 = 11.3
or another way.
sin (62) = 10 /c ---> c = 10/ sin (62) = 10 / 0.88 = 11.3
So Angle of A = 28 degree.
a = 5. 3
c = 11.3.
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First question seems incomplete :
Answer:
40 ways
Step-by-step explanation:
Question B:
Number of boys = 6
Number of girls = 4
Number of people in committee = 3
Number of ways of selecting committee with atleast 2 girls :
We either have :
(2 girls 1 boy) or (3girls 0 boy)
(4C2 * 6C1) + (4C3 * 6C0)
nCr = n! ÷ (n-r)!r!
4C2 = 4! ÷ 2!2! = 6
6C1 = 6! ÷ 5!1! = 6
4C3 = 4! ÷ 1!3! = 4
6C0 = 6! ÷ 6!0! = 1
(6 * 6) + (4 * 1)
36 + 4
= 40 ways
