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givi [52]
3 years ago
5

Complete the proof please. A. SAS B. ASA C. AAS D.HL

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
6 0

Option B:

ASA congruence

Solution:

Step 1: Given

\overline{Q S} \perp \overline{Q T}

Step 2: Given

\overline{R T} \perp \overline{R S}

Step 3: Given

\overline{Q U} \cong \overline{R U} (Included side)

Step 4: All right angles are congruent.

\angle Q \cong \angle R (Angle)

Step 5: By vertical angle theorem

\angle Q U T \cong \angle R U S (Angle)

Step 6: By ASA congruence

QU and RU are included side of corresponding angles.

Therefore by ASA congruence rule,

\Delta Q T U \cong \Delta R S U

Option B is the correct answer.

Hence proved.

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Match each pair of points with the coordinate that will make a right triangle with its hypotenuse along the graph shown.
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1 is B
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6 0
3 years ago
A company sells widgets. The amount of profit, y, made by the company, is related to the selling price of each widget, x, by the
nalin [4]

Answer:

$519

Step-by-step explanation:

Given the amount of profit made expressed as y=-2x^2+105x-859

At maximum profit, dy/dx = 0

dy/dx = -4x + 105

0 = -4x + 105

4x = 105

x = 105/4

x = 26.25

Substitute into the original function

y=-2x^2+105x-859

y=-2(26.25)^2+105(26.25)-859

y = - 1,378.125+2,756.25-859

y = 519.125

Hence the maximum amount of profit the company can make is $519

8 0
3 years ago
A delivery person uses a service elevator to bring boxes of books up to an office. The delivery person weighs 190 lb and each bo
vagabundo [1.1K]

Answer:

25 boxes.

Step-by-step explanation:

We have the inequality:

190 + 60x ≤ 1740  where  x = the number of boxes of books.

60x  ≤  1740 - 190

60x   ≤  1550

x ≤ 25.83.

6 0
3 years ago
Read 2 more answers
A ball is floating partially submerged in a liquid. Which quantity equals the buoyant force acting on the ball? mass of the ball
REY [17]
For something to float the buoyant force ( force pushing up on the object to keep it floating) needs to equal the weight of the object

 the answer would be: <span>weight of the ball</span>



6 0
3 years ago
Work out the volume of the shape​
pashok25 [27]

Answer:

\large\boxed{V=\dfrac{1,421\pi}{3}\ cm^3}

Step-by-step explanation:

We have the cone and the half-sphere.

The formula of a volume of a cone:

V_c=\dfrac{1}{3}\pi r^2H

r - radius

H - height

We have r = 7cm and H = (22-7)cm=15cm. Substitute:

V_c=\dfrac{1}{3}\pi(7^2)(15)=\dfrac{1}{3}\pi(49)(15)=\dfrac{735\pi}{3}\ cm^3

The formula of a volume of a sphere:

V_s=\dfrac{4}{3}\pi R^3

R - radius

Therefore the formula of a volume of a half-sphere:

V_{hs}=\dfrac{1}{2}\cdot\dfrac{4}{3}\pi R^3=\dfrac{2}{3}\pi R^3

We have R = 7cm. Substitute:

V_{hs}=\dfrac{2}{3}\pi(7^3)=\dfrac{2}{3}\pi(343)=\dfrac{686\pi}{3}\ cm^3

The volume of the given shape:

V=V_c+V_{hs}

Substitute:

V=\dfrac{735\pi}{3}+\dfrac{686\pi}{3}=\dfrac{1,421\pi}{3}\ cm^3

7 0
3 years ago
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