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givi [52]
3 years ago
5

Complete the proof please. A. SAS B. ASA C. AAS D.HL

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
6 0

Option B:

ASA congruence

Solution:

Step 1: Given

\overline{Q S} \perp \overline{Q T}

Step 2: Given

\overline{R T} \perp \overline{R S}

Step 3: Given

\overline{Q U} \cong \overline{R U} (Included side)

Step 4: All right angles are congruent.

\angle Q \cong \angle R (Angle)

Step 5: By vertical angle theorem

\angle Q U T \cong \angle R U S (Angle)

Step 6: By ASA congruence

QU and RU are included side of corresponding angles.

Therefore by ASA congruence rule,

\Delta Q T U \cong \Delta R S U

Option B is the correct answer.

Hence proved.

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3 years ago
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Given that:

Consider it is \sqrt{10} instead of 10 on two places.

\sqrt{10} is between 3  and 4. So, Beau thinks a good estimate for \sqrt{10} is = 3.5.

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To find \sqrt{10}, Beau found 3² = 9 and 4² = 16.

He said that since 10 is between 9 and 16.

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