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givi [52]
4 years ago
5

Complete the proof please. A. SAS B. ASA C. AAS D.HL

Mathematics
1 answer:
riadik2000 [5.3K]4 years ago
6 0

Option B:

ASA congruence

Solution:

Step 1: Given

\overline{Q S} \perp \overline{Q T}

Step 2: Given

\overline{R T} \perp \overline{R S}

Step 3: Given

\overline{Q U} \cong \overline{R U} (Included side)

Step 4: All right angles are congruent.

\angle Q \cong \angle R (Angle)

Step 5: By vertical angle theorem

\angle Q U T \cong \angle R U S (Angle)

Step 6: By ASA congruence

QU and RU are included side of corresponding angles.

Therefore by ASA congruence rule,

\Delta Q T U \cong \Delta R S U

Option B is the correct answer.

Hence proved.

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Which nets match Figure g shown below <br><br> Select all that apply <br><br> Need help
777dan777 [17]

Answer:

Step-by-step explanation:

i cant see figure g

6 0
3 years ago
The prism is completely filled with 1750 cubes that have edge length of 1/5 ft. What is the volume of the prism? Enter your answ
IgorC [24]

Answer:

14 ft³

Step-by-step explanation:

First, find the volume of a single cube: V = s³, where s = side length

V = s³; s = 1/5

V = (1/5)³

V = 0.008 ft³

**Note: (1/5)³ is equal to 1/125 as a fraction. I put it down in decimal form because it's easier for me to work with decimals.**

Now, to find the volume of the prism (which is <u><em>completely</em></u> filled with cubes), multiply the volume of one cube by the total number of cubes: 1750.

(1750)(0.008)

14 ft³

The volume of the prism is 14 ft³.

Hope this helps!

8 0
3 years ago
Gilda drove 650miles at an average speed of 50 miles per hour.how many miles per hour faster would she have had to drive in orde
zzz [600]
T=650mi(hr/50mi)=13 hr

t-1=12 hr

12=650/(50+v)  multiply both sides by 50+v

600+12v=650  subtract 600 from both sides

12v=50  divide both sides by 12

v=25/6 mph

v≈4.17mph


6 0
3 years ago
Find the absolute maximum and minimum values of the following function on the given interval. If there are multiple points in a
Bond [772]

f(x)=3\sin x+3\cos x\implies f'(x)=3\cos x-3\sin x

f has critical points where f'=0:

3\cos x-3\sin x=0\implies\cos x=\sin x\implies\tan x=1\implies x=\pm\dfrac\pi4+2n\pi

where n is any integer. We get solutions in the interval \left[0,\frac\pi3\right] for n=0, for which x=\frac\pi4.

At this critical point, we have f\left(\frac\pi4\right)=3\sqrt2\approx4.243.

At the endpoints of the given interval, we have f(0)=3 and f\left(\frac\pi3\right)=\frac{3+3\sqrt3}2\approx4.098.

So we have the extreme values

\max\limits_{x\in\left[0,\frac\pi3\right]}f=3\sqrt2

\min\limits_{x\in\left[0,\frac\pi3\right]}f=3

8 0
4 years ago
A woman is standing at the edge of a slow-moving river which is one mile wide, and she wishes to return to her campground on the
vesna_86 [32]

Answer:

the best option would be to swim

Step-by-step explanation:

Hello! To solve this problem we must follow the following steps.

1. remember the concept of uniform motion with constant speed, which establishes the following equation

t=\frac{X}{V}

where

t=time

x=distance

V=speed

2. Calculate the time it takes to swim and calculate the time it takes to walk

walking:

x=10mile

v=5milles/h

t=\frac{10}{5} =2h

swimming

x=1mile

v=3milles/h

t=\frac{1}{3} =0.3h

3. Compare both results and choose the one with the least time.

as you can see it takes less time swimming, so this would be the best way

7 0
3 years ago
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