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Sever21 [200]
2 years ago
5

(b) A line has the equation y = 6x + 11

Mathematics
2 answers:
Ganezh [65]2 years ago
6 0

Hey there!

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marin [14]2 years ago
4 0

Hi, to begin, the ordered pair value (-3, 15) has an x-value of -3. So, to see if it lies on the line of your equation y = 6x + 11, plug -3 in for x. This gives you y = 6(-3) + 11 = -7 So the ordered pair answer for this would be (-3, -7) and not (-3, 15). So the answer is no.

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Solve for x. Round to the nearest hundredth
PIT_PIT [208]

Given that the length of one leg is 6 and the angle is 40°

The hypotenuse is x.

We need to determine the value of x.

<u>Value of x:</u>

The value of x can be determined using the trigonometric ratio.

Thus, we have;

cos \ \theta=\frac{adj}{hyp}

Substituting the values, we get;

cos \ 45^{\circ}=\frac{6}{x}

Simplifying, we have;

x=\frac{6}{cos \ 45^{\circ}}

x=\frac{6}{0.766}

Dividing, we get;

x\approx7.83

Therefore, the value of x is 7.83(app.)

Hence, Option A is the correct answer.

3 0
3 years ago
What is the solution set of the given system?
AVprozaik [17]

What is the system? (Is there supposed to be an image?)

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3 years ago
The formula for the area of a triangle is a =1/2bh in which b represents the length of the base Andy represents the height. If a
aleksandrvk [35]
A=1/2bh
Data:
a=192 mm²
h=12 mm


therefore:
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192 mm²=6b mm
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b=32 mm

Answer: the measure of the base is 32 mm
4 0
3 years ago
Read 2 more answers
The quotient of (x^3+3x^2-4x-12)/(x^2+5x+6)
Elis [28]

Answer: The quotient is (x-2).

Step-by-step explanation:

Since we have given that

f(x)=(x^3+3x^2-4x-12)\\\\and\\\\g(x)=x^2+5x+6\\\\So,\ \frac{\left(x^3+3x^2-4x-12\right)}{\left(x^2+5x+6\right)}

Now, we have to find the quotient of the above expression.

So, here we go:

Factorise\ (x^3+3x^2-4x-12)\\\\=\left(x^3+3x^2\right)+\left(-4x-12\right)\\\\=-4\left(x+3\right)+x^2\left(x+3\right)\\\\=\left(x+3\right)\left(x^2-4\right)

Now, we will divide the above simplest form with g(x):

\frac{\left(x+3\right)\left(x^2-4\right)}{\left(x+2\right)\left(x+3\right)}\\\\=\frac{x^2-4}{x+2}\\\\=\frac{\left(x+2\right)\left(x-2\right)}{x+2}\ using\ (a^2-b^2)=(a+b)(a-b)\\\\=x-2

Hence, the quotient is (x-2).


6 0
3 years ago
Read 2 more answers
Which of these ordered pairs is a solution for this linear inequality 3y-2x&lt;=6? A. (-4,2) B. (1,3) C. (2,-4) D. (2,4)
Usimov [2.4K]

Answer:

C

Step-by-step explanation:

3y-2x<=6

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-12-4<=6

-16<=6

4 0
3 years ago
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