Answer: 260 downloads of the standard version were there.
Step-by-step explanation:
Let x represent the number of downloads of the standard version.
Let y represent the number of downloads of the high-quality version.
Yesterday, the high-quality version downloaded four times as often as the standard version. It means that
y = 4x
The size of the standard version is 2.9 megabytes (MB). the size of the high-quality version is 4.6 MB. the total size downloaded for the two versions was 5538 MB. It means that
2.9x + 4.6y = 5538- - - - - - - - - - - -1
Substituting y = 4x into equation 1, it becomes
2.9x + 4.6 × 4x = 5538
2.9x + 18.4x = 5538
21.3x = 5538
x = 5538/21.3
x = 260
<em>$29178.25</em>
- Step-by-step explanation:
<em>x = p(1 - r)ⁿ</em>
<em>p = original price</em>
<em>r = 8.3% = 0.083</em>
<em>n = 5 years</em>
<em>x = $45000(1 - 0.083)⁵</em>
<em>= $45000ₓ0.917⁵</em>
<em>= $45000ₓ0.64840548256</em>
<em>= </em><em>$29178.25</em>
Im pretty sure that the answe would be northern plains
A. 32500
b. 60,400
c. 2.4 x 10 ^ -6
d. 1.47 x 10 ^3
Answer:
The factorization of 
is 
Step-by-step explanation:
This is a case of factorization by <em>sum and difference of cubes</em>, this type of factorization applies only in binomials of the form 
or 
. It is easy to recognize because the coefficients of the terms are <u><em>perfect cube numbers</em></u> (which means numbers that have exact cubic root, such as 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.) and the exponents of the letters a and b are multiples of three (such as 3, 6, 9, 12, 15, 18, etc.).
Let's solve the factorization of by using the <em>sum and difference of cubes </em>factorization.
1.) We calculate the cubic root of each term in the equation , and the exponent of the letter x is divided by 3.
![\sqrt[3]{729x^{15}} =9x^{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B729x%5E%7B15%7D%7D%20%3D9x%5E%7B5%7D)
then ![\sqrt[3]{10^{3}} =10](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B10%5E%7B3%7D%7D%20%3D10)
So, we got that
which has the form of which means is a <em>sum of cubes.</em>
<em>Sum of cubes</em>
with 
y 
2.) Solving the sum of cubes.
.
