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artcher [175]
2 years ago
7

Hope u can do it HELP MATH

Mathematics
2 answers:
Nostrana [21]2 years ago
5 0

Answer:

the right answer would be 13

zhenek [66]2 years ago
3 0

Answer:

13

Step-by-step explanation:

f (x) = x/2 + 8

If x = 10, replace the x with 10.

f (x) = 10 / 2 + 8

f (x) = 5 + 8

f (x) = 13

Always happy to help <3

You might be interested in
Please help me with this
skelet666 [1.2K]
D) 8.17 x 10^8


910000000 - 93000000 = 817000000 

817000000 ---> 8.17 x 10^8
5 0
3 years ago
Use the figure below to find the answer.
Serhud [2]

Answer: \frac{7\sqrt{2}}{2}

Step-by-step explanation:

\sin 45^{\circ}=\frac{7}{y}\\\\\frac{1}{\sqrt{2}}=\frac{7}{y}\\\\y=\frac{7}{\sqrt{2}}=\boxed{\frac{7\sqrt{2}}{2}}

4 0
2 years ago
Please help <br> A. 63<br> B. 72<br> C. 81<br> D. 108
Tom [10]

Answer:

<u>D.108</u> is correct.

Step-by-step explanation:

6*3 = 18

18*4 = 72

6*6 = 32

72 + 32 = 108

Have a nice day!

5 0
3 years ago
Answers? Thank you for helping
4vir4ik [10]

Answer:

1. no solution

2. one solution

3. no solution

4. no solution

Step-by-step explanation:

5 0
2 years ago
In the diagram below, assume that all points are given in rectangular coordinates. Determine the polar coordinates for each poin
Korolek [52]

Step-by-step explanation:

We have cartisean points. We are trying to find polar points.

We can find r by applying the pythagorean theorem to the x value and y values.

r  {}^{2} =  {x}^{2}  +  {y}^{2}

And to find theta, notice how a right triangle is created if we draw the base(the x value) and the height(y value). We also just found our r( hypotenuse) so ignore that. We know the opposite side and the adjacent side originally. so we can use the tangent function.

\tan(x)  =  \frac{y}{x}

Remeber since we are trying to find the angle measure, use inverse tan function

\tan {}^{ - 1} ( \frac{y}{x} )  =

Answers For 2,5

{2}^{2}  +  {5}^{2}  =  \sqrt{29}  = 5.4

So r=sqr root of 29

\tan {}^{ - 1} ( \frac{5}{2} )  = 68

So the answer is (sqr root of 29,68).

For -3,3

{ -3 }^{2}  +  {3}^{2}  =  \sqrt{18}  = 3 \sqrt{2}

\tan {}^{ - 1} ( \frac{3}{ - 3} )  =  - 45

Use the identity

\tan(x)  =  \tan(x + \pi)

So that means

\tan(x)  = 135

So our points are

(3 times sqr root of 2, 135)

For 5,-3.5

{5}^{2}  +  {3.5}^{2}  =  \sqrt{37.25}

\tan {}^{ - 1} ( \frac{ - 3.5}{ - 5} )  = 35

So our points are (sqr root of 37.25, 35)

For (0,-5.4)

{0}^{2}  +  { - 5.4}^{2}  = \sqrt{}  29.16 = 5.4

So r=5.4

\tan {}^{ - 1}  (0)  = undefined

So our points are (5.4, undefined)

4 0
3 years ago
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