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DIA [1.3K]
3 years ago
14

Please show work! Thank you

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
4 0
A) The greatest rectangular area will be the area of a square 10 m on each side, 100 m^2.

b) The new dimensions will be 11 m × 11 m.
.. The new area will be (11 m)^2 = 121 m^2.

c) The area was increased by 121 m^2 -100 m^2 = 21 m^2, or 21%.

d) Yes, and no.
.. If you increase the dimensions by 10%, the area will increase by 21%.
.. (40 m)^2 = 1600 m^2
.. (44 m)^2 = 1936 m^2 = 1.21*(1600 m^2), an increase of 21% over the original.

.. If you increase the dimensions by 1 unit, the area will increase by (2x+1) square units, where x is the side of the original. For x≠10, this is not 21 square units.
.. (41 m)^2 = 1681 m^2 = 1600 m^2 +(2*40 +1) m^2 = 1600 m^2 +81 m^2
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Y=2x-8 is the answer
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Timmy writes the equation f(x) = 1/4x – 1. He then doubles both of the terms on the right side to create the equation g(x) = 1/2
Assoli18 [71]

Answer:

The answer is

Step-by-step explanation:

The line of g(x) is steeper and has a lower y-intercept

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That’s the answer <3

3 0
3 years ago
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Write the following number as ratios of integers
s2008m [1.1K]

Our goal here is to somehow "surgically remove" the repeating part of the number, so let's start by putting the original value in a variable and messing around with it a bit.

We'll let x=7.\overline{6}. We want to cut the 0.\overline{6} bit off completely, so let's create the scalpel that'll let us do that. If x=7.\overline{6}, then we can also say that 10x=76.\overline{6}. Maybe I was lying a bit: the x is our real scalpel here, and 10x is where we'll be making the cut. Mathematically, a "cut" is almost always shorthand for subtraction, so let's see what our operation (cutting x off of 10x) leaves us with:

10x-x=76.\overline{6}-7.\overline{6}\\9x=69

The operation was a success! We can now simply divide either side by 9 to find x = 69/9, which, when reduced by dividing the numerator and denominator by 3, gives us x=23/3

7 0
3 years ago
Match each radical equation with the corresponding value of x
Radda [10]
64^(4/3)
= 256

32^(3/5)
= 8

625^(3/4)
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4 0
3 years ago
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Please help!! This is so confusing! 100 points!!
masya89 [10]

Answer:

The value of the expression given is:

  • 4

Step-by-step explanation:

First, you must divide the expression in three, and to the final, you can multiply it:

  1. [(3^8)*(2^(-5))*(9^0)]^(-2)
  2. [(2^(-2))/(3^3)]^4
  3. 3^28

Now, we can solve each part one by one:

<em>First part. </em>

  • 3^8 = 6561
  • 2^(-5) = 0.03125
  • 9^0 = 1 (Whatever number elevated to 0, its value is 1)
  • (6561 * 0,03125 * 1) = 205.03125

And we elevate this to -2:

  • 205.03125^-2 = 2<u>.378810688*10^(-5)</u> or <u>0.00002378810688 </u>

<em>Second part. </em>

  • 2^(-2) = 0.25
  • 3^3 = 27
  • 0.25 / 27 = 9.259259259 * 10^(-3) or 0.00925925925925

And we elevate this to 4:

  • 0.00925925925925^4 = <u>7.350298528 * 10^(-9)</u> or <u>0.000000007350298528 </u>

<em>Third Part. </em>

  • 3^28 = <u>2.287679245 * 10^13</u> or <u>22876792450000</u>

At last, we multiply all the results obtained:

  • 0.00002378810688 * 0.000000007350298528 * 22876792450000 = <u>3.999999999999999999</u> approximately <u>4</u>

<u><em>We approximate the value because the difference to 4 is minimal, which could be obtained if we use all the decimals in each result</em></u>.

3 0
3 years ago
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