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3 years ago

Pls help 0.4x3.2 step by step pls

Mathematics

1 answer:

horsena [70]3 years ago

3 0

Answer:

1.28

Step-by-step explanation:

0.4 x 3.2 = 1.28

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The number of adults who attend a county fair (measured in hundreds of people) is represented by the function a(d)=−0.3d2+4d+9 ,

Lesechka [4]

Given is the function for number of adults who visit fair at day 'd' after its opening, a(d) = −0.3d² + 4d + 9.

Given is the function for number of children who visit fair at day 'd' after its opening, c(d) = −0.2d² + 5d + 11.

Any function f(d) to find excess of children more than adults can be written as follows :-

f(d) = c(d) - a(d).

⇒ f(d) = (−0.2d² + 5d + 11) - (−0.3d² + 4d + 9)

⇒ f(d) = -0.2d² + 0.3d² + 5d - 4d + 11 - 9

⇒ f(d) = 0.1d² + d + 2

6 0

3 years ago

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Please help !!!!!!!!!!!!!!!!!!! what is A

algol13

Answer:

Step-by-step explanation:

a=11/12

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3 years ago

Write the ratio as a fraction in lowest terms 17 minutes to 2 hours

8_murik_8 [283]

17:2 equals is 17/19 of the whole and part b is 2/19 of the whole

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4 years ago

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What is value of x Enter your answer in the box.

borishaifa [10]

Answer:

x=10

Step-by-step explanation:

Lets use a ratio.

3:2 (12 to 8)

We need to scale the x+4 up 3/2 to be equal to 2x+1

(3/2) x+4 = 2x+1

1.5x+6=2x+1

-1.5x -1.5x

6=0.5x+1

-1 -1

0.5x=5

x=10

4 0

3 years ago

An industry representative claims that 10 percent of all satellite dish owners subscribe to at least one premium movie channel.

Greeley [361]

Answer: 1) 0.6561 2) 0.0037

Step-by-step explanation:

We use Binomial distribution here , where the probability of getting x success in n trials is given by :-

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

, where p =Probability of getting success in each trial.

As per given , we have

The probability that any satellite dish owners subscribe to at least one premium movie channel. : p=0.10

Sample size : n= 4

Let x denotes the number of dish owners in the sample subscribes to at least one premium movie channel.

1) The probability that none of the dish owners in the sample subscribes to at least one premium movie channel = $P(X=0)=^4C_0(0.10)^0(1-0.10)^{4}$

$=(1)(0.90)^4=0.6561$

∴ The probability that none of the dish owners in the sample subscribes to at least one premium movie channel is 0.6561.

2) The probability that more than two dish owners in the sample subscribe to at least one premium movie channel.

= $P(X>2)=1-P(X\leq2)\\\\=1-[P(X=0)+P(X=1)+P(X=2)]\\\\= 1-[0.6561+^4C_1(0.10)^1(0.90)^{3}+^4C_2(0.10)^2(0.90)^{2}]\\\\=1-[0.6561+(4)(0.0729)+\dfrac{4!}{2!2!}(0.0081)]\\\\=1-[0.6561+0.2916+0.0486]\\\\=1-0.9963=0.0037$

∴ The probability that more than two dish owners in the sample subscribe to at least one premium movie channel is 0.0037.

8 0

3 years ago