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Gre4nikov [31]
3 years ago
7

Math hel pls, thank u

Mathematics
1 answer:
professor190 [17]3 years ago
4 0

Answer:

Step-by-step explanation:

8) C

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State the value of 'x' in this equation, and explain why you know this to be true without doing any calculations.
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Answer:

x=9

if

a^b = a^c

then b=c

so in this case x=9

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1 year ago
Distributive property of 3(2x + 7)
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6x+21

Step-by-step explanation:

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the price of an item has increased 15% since last year. However l a person can buy the item for a 25%employee discount. The empl
Fiesta28 [93]

Let us assume last year the price of the item = $x.

After increase in price by 15% the new price = x + 15% of x = x+ 0.15x = 1.15x.

There is a 25% discount for employee.

25% of 1.15x = 0.25 × 1.15x = 0.2875 x.

Price after discount = 1.15x - 0.2875 x = 0.8625x.

The employee pays $172.50.

Therefore,

0.8625x = 172.50.

Dividing both sides by 0.08625.

\frac{0.8625x }{ 0.8625} =\frac{172.50}{0.8625}

<h3>x=200.</h3><h3>Therefore, last year the price was $200.</h3>
8 0
3 years ago
The following results come from two independent random samples taken of two populations.
photoshop1234 [79]

Answer:

(a)\ \bar x_1 - \bar x_2 = 2.0

(b)\ CI =(1.0542,2.9458)

(c)\ CI = (0.8730,2.1270)

Step-by-step explanation:

Given

n_1 = 60     n_2 = 35      

\bar x_1 = 13.6    \bar x_2 = 11.6    

\sigma_1 = 2.1     \sigma_2 = 3

Solving (a): Point estimate of difference of mean

This is calculated as: \bar x_1 - \bar x_2

\bar x_1 - \bar x_2 = 13.6 - 11.6

\bar x_1 - \bar x_2 = 2.0

Solving (b): 90% confidence interval

We have:

c = 90\%

c = 0.90

Confidence level is: 1 - \alpha

1 - \alpha = c

1 - \alpha = 0.90

\alpha = 0.10

Calculate z_{\alpha/2}

z_{\alpha/2} = z_{0.10/2}

z_{\alpha/2} = z_{0.05}

The z score is:

z_{\alpha/2} = z_{0.05} =1.645

The endpoints of the confidence level is:

(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}

2.0 \± 1.645 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}

2.0 \± 1.645 * \sqrt{\frac{4.41}{60}+\frac{9}{35}}

2.0 \± 1.645 * \sqrt{0.0735+0.2571}

2.0 \± 1.645 * \sqrt{0.3306}

2.0 \± 0.9458

Split

(2.0 - 0.9458) \to (2.0 + 0.9458)

(1.0542) \to (2.9458)

Hence, the 90% confidence interval is:

CI =(1.0542,2.9458)

Solving (c): 95% confidence interval

We have:

c = 95\%

c = 0.95

Confidence level is: 1 - \alpha

1 - \alpha = c

1 - \alpha = 0.95

\alpha = 0.05

Calculate z_{\alpha/2}

z_{\alpha/2} = z_{0.05/2}

z_{\alpha/2} = z_{0.025}

The z score is:

z_{\alpha/2} = z_{0.025} =1.96

The endpoints of the confidence level is:

(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}

2.0 \± 1.96 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}

2.0 \± 1.96* \sqrt{\frac{4.41}{60}+\frac{9}{35}}

2.0 \± 1.96 * \sqrt{0.0735+0.2571}

2.0 \± 1.96* \sqrt{0.3306}

2.0 \± 1.1270

Split

(2.0 - 1.1270) \to (2.0 + 1.1270)

(0.8730) \to (2.1270)

Hence, the 95% confidence interval is:

CI = (0.8730,2.1270)

8 0
3 years ago
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Fofino [41]
Supplementary is when it is a straight line that is equal to 180 degrees and complementary is a right angle which is 90 degrees
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