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Arturiano [62]
3 years ago
15

Given the midpoint (1.5,1.5) and the endpoint (5,7) where is the other endpoint located

Mathematics
1 answer:
earnstyle [38]3 years ago
8 0

The formula of a midpoint:

M_{AB}\left(\dfrac{x_A+x_B}{2},\ \dfrac{y_A+y_B}{2}\right)

We have:

M(1.5,\ 1.5)\to x_M=1.5,\ y_M=1.5\\A(5,\ 7)\to x_A=5,\ y_A=7

Substitute

\dfrac{5+x_B}{2}=1.5\qquad|\cdot2\\\\5+x_B=3\qquad|-5\\\\x_B=-2\\\\\dfrac{7+y_B}{2}=1.5\qquad|\cdot2\\\\7+y_B=3\qquad|-7\\\\y_B=-4

<h3>Answer: (-2, -4)</h3>
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Given the functions below, find f(x) - g(x) f(x) = 3x^2 + 2x + 1 g(x) = x^2 - 6x + 3
saveliy_v [14]

Answer:

Here is your answer.....

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5 0
3 years ago
PLEASE HELP! Identify the rule for the function table.
fgiga [73]
Hello!

You have to find what the rule is

12/24 = 0.5
6/12 = 0.5
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They multiply x by 0.5

the rule is multiply x by 0.5 or y = 0.5x

Hope this helps!
4 0
3 years ago
Use the information provided to write the equation of each circle​
Nadusha1986 [10]

Answer:

1.

centre(h,k)=(-13,9)

radius (r)=6

we have

equation of the circle is

(x-h)²+(y-k)²=r²

(x+13)²+(y-9)²=6²

x²+26x+169+y²-18y+81=36

x²+y²+26x-18y+169+81-36=0

x²+y²+26x-18y +214=0

is a required equation of the circle.

2.

centre(h,k)=(1,-1)

radius (r)=11

we have

equation of the circle is

(x-h)²+(y-k)²=r²

(x-1)²+(y+1)²=11²

x²-2x+1+y²+2y+1=121

x²+y²-2x+2y=121-2

x²+y²-2x+2y=119

is a required equation of the circle.

4 0
3 years ago
Help would really be appreciated. The question is in the picture.
Vikentia [17]
|-11+8|=|-3|=3. Plug in f(-11)
4 0
3 years ago
A number was subtracted from 15. After which, that result was multiplied by 5. This result was then divided by 5 for a result of
likoan [24]

Answer:

14

Step-by-step explanation:

15-14 = 1

1*5=5

5/1=1

6 0
2 years ago
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