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katrin [286]
3 years ago
14

A school has a square playground with each side

Mathematics
1 answer:
aleksklad [387]3 years ago
6 0

Answer:

10 inches

Step-by-step explanation:

The length of the playground in its actual size is 120 feet.

The scale drawing uses a scale of 1 inch to 12 feet.

This means that 1 inch in the drawing equals 12 feet in actual size.

Therefore, the length of the playground on the scale drawing is:

1 inch = 12 feet

x = 120 feet

Cross-multiply:

120 * 1 = 12 * x

=> x = 120 / 12 = 10 inches

The length of a side of the playground on  the scale drawing is 10 inches.

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Determine the written description of the complement of the given event. When 13 computers are shipped​, at least one of them is
julsineya [31]

Answer:

A. None of them are defective

True that's equivalent since none defective means 0 defective

Step-by-step explanation:

For this case we have a total of 13 computers and we define the event:

E= "At least one of them is defective"

When we say at last one means that can be 1,2,3,4,5,6,7,8,9,10,11,12 or 13

The complement for this case is E' ="None of them is defective"

Let's analyze one by one the possible options:

A. None of them are defective

True that's equivalent since none defective means 0 defective

B. None of them are free of defects

False thats note equivalent since that means all have defects and that's not the complement.

C. More than one of them are free of defects

False we are interested on the complement and on this case 1 or more defective is not the complement for this case.

D. All of them are defective

False the complement is defined as non of them defective and for this case is not the correct way.

6 0
3 years ago
4(5x – 9) = -2(x + 7) solve and justify each step
Alexandra [31]

Step-by-step explanation:

4(5x-9)=-2(x+7)

4*5x-4*9=-2*x-2*7

20x-36=-2x-14

20x+2x=-14+36

22x=22

x=22/22

x=1

5 0
3 years ago
The difference of two positive numbers is 7 and the sum of their squares is 109. Find the numbers.
Ray Of Light [21]

Answer:

Numbers\ are\ 58\ and\ 51.

Step-by-step explanation:

The the numbers are x\ and\ y.

<em>Difference:</em>

<em></em>Difference\ of\ numbers=7\\\\x-y=7....................eq(1)<em></em>

<em>Sum:</em>

<em></em>Sum\ of\ numbers=109\\\\x+y=109...........................eq(2)<em></em>

<em></em>

Solve eq(1) and eq(2).

eq(1)+eq(2)\\\\x-y+x+y=7+109\\\\2x=116\\\\x=58\\\\Now\ from\ equation\ 1\\\\x-y=7\\\\y=x-7\\\\y=58-7\\\\y=51

7 0
3 years ago
If there are 2.2 pounds in 1 kilogram how many pounds are there in x kilograms?
nirvana33 [79]

Answer:

P=x/2.2

Step-by-step explanation:

We can create an equation to solve this.

Let the number of pounds be P

Let the number of kilograms be X

Now, we know that for 1 kilogram, there is 2.2 pounds.

Therefore if we have 1 kilogram (X) then we will have 2.2 pounds (P).

<u>X=2.2P</u>

All you have to do now is rearrange the equation to find the number of pounds in x kilograms. To do this divide both sides by 2.

Therefore you will get P=x/2.2

5 0
3 years ago
What is 25-6x-12-2x simplified
liraira [26]
- 8x+13=-( 8x-13) <--------'-------
6 0
3 years ago
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