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lutik1710 [3]
2 years ago
14

Which equation can be use to solve for x in the parallelogram below ?

Mathematics
2 answers:
Sauron [17]2 years ago
7 0

Answer:

Below.

Step-by-step explanation:

I can't read it very well but one equation might be

2x + 8 = 3x - 12

(because the opposite sides of a parallelogram  are congruent.

alukav5142 [94]2 years ago
7 0

Explanation:

Opposite angles of a parallelogram are equal.

<em>B. (3x - 12)° = (2x + 8)°</em>

This equation can be used to solve x.

3x - 12 = 2x + 8

3x - 2x = 12 + 8

<em>x = 20°</em>

Verification:

3(20) - 12 = 2(20) + 8

60 - 12 = 40 + 8

48° = 48°

<u><em>Hence, verified.</em></u>

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Answer:

If your install Bratleby on your device, It will help you with this. But you will have to put in an email. and it will give 10  questions to answer for free. Sorry that I cannot help you with this.

Step-by-step explanation:

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3 years ago
What is the remainder when the polynomial 6x2+11x−3 is divided by 2x−1?
o-na [289]

Answer: 4

There are three different ways to find the remainder.  Since I don't know which lesson you are working on, I will show you all three methods.

<u>Long Division:</u>

           <u>3x  +  7      </u>

2x - 1 ) 6x² + 11x - 3

       -  <u>(6x²  -  3x)</u>   ↓

                    14x  - 3

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                              4    

<u>Synthetic Division:</u>

2x - 1 = 0   ⇒   x = \frac{1}{2}


\frac{1}{2}   | 6      11     -3

    <u>| ↓       3     7</u>

      6      14    4

<u>Remainder Theorem:</u>

2x - 1 = 0   ⇒   x = \frac{1}{2}

f(x) = 6x² + 11x - 3

f(\frac{1}{2}) = 6(\frac{1}{2})² + 11(\frac{1}{2}) - 3

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      = \frac{8}{2}

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3 years ago
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Finding diagonal sum

\\ \sf\longmapsto 0.7+1.0+1.3

\\ \sf\longmapsto 0.7+2.3

\\ \sf\longmapsto 3.0

#b

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  • y=0.6

\\ \sf\longmapsto xy=0.9(0.6)

\\ \sf\longmapsto xy=0.54

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Answer:

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We are given that a bottling company uses a filling machine to fill plastic bottles with cola. And the contents vary according to a Normal distribution with Mean, μ = 298 ml and Standard deviation, σ = 3 ml .

 Let    Z = \frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)  where, Xbar = mean contents of six randomly

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Answer:

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