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2 years ago

14

Which equation can be use to solve for x in the parallelogram below ?

2 answers:

Sauron [17]2 years ago

7 0

Answer:

Below.

Step-by-step explanation:

I can't read it very well but one equation might be

2x + 8 = 3x - 12

(because the opposite sides of a parallelogram are congruent.

alukav5142 [94]2 years ago

7 0

Explanation:

Opposite angles of a parallelogram are equal.

<em>B. (3x - 12)° = (2x + 8)°</em>

This equation can be used to solve x.

3x - 12 = 2x + 8

3x - 2x = 12 + 8

<em>x = 20°</em>

Verification:

3(20) - 12 = 2(20) + 8

60 - 12 = 40 + 8

48° = 48°

<u><em>Hence, verified.</em></u>

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An open-top box with a square base is to have a volume of 4 cubic feet. Find the dimensions of the box (in ft) that can be made

Lemur [1.5K]

Answer:

The dimension of box= $2ft\times 2ft\times 1ft$

Step-by-step explanation:

We are given that

Volume of box=4 cubic feet

Let x be the side of square base and h be the height of box

Volume of box= $lbh=x^2h$

$4=x^2h$

$h=\frac{4}{x^2}$

Now, surface area of box,A= $x^2+4xh$

$A=x^2+4x(\frac{4}{x^2})=x^2+\frac{16}{x}$

$\frac{dA}{dx}=2x-\frac{16}{x^2}$

$\frac{dA}{dx}=0$

$2x-\frac{16}{x^2}=0$

$2x=\frac{16}{x^2}$

$x^3=8$

$x=2$

$\frac{d^2A}{dx^2}=2+\frac{32}{x^3}$

Substitute x=2

$\frac{d^2A}{dx^2}=2+\frac{32}{2^3}=2+4=6>0$

Hence, the area of box is minimum at x=2

Therefore, side of square base,x=2 ft

Height of box,h= $\frac{4}{2^2}=1 ft$

Hence, the dimension of box= $2ft\times 2ft\times 1ft$

5 0

2 years ago

38% of what is 152? Show work

marusya05 [52]

Take that certain number we are looking for as 'n'

38% ⇒ 0.38

0.38n = 152

Divide by 0.38

0.38n = 152
/0.38 /0.38

n = 400

So 38% of 400 is 152.

3 0

3 years ago

Read 2 more answers

Ivanna purchased a prepaid phone card for $30. Long distance calls cost 16 cents a minute using this card. Ivanna used her card

Wewaii [24]

Answer:

11 Minutes

Step-by-step explanation:

$30 - $28.24 = $1.76

$1.76/ 0.16 Cents /minute = 11 Minutes

7 0

2 years ago

Two drivers, Alison and Kevin, are participating in a drag race. Beginning from a standing start, they each proceed with a const

Vilka [71]

Answer:

Alison wins against Kevin by 0.93 s

Step-by-step explanation:

Alison covers the last 1/4 of the distance in 3 seconds, at a constant acceleration $a_a$ , we have the following equation of motion

$s/4 = a_at_a^2/2$

where s (m) is the total distance, ta = 3 s is the time

$s = 4a_a3^2/2 = 18a_a$

$a_a = s/18$

Similarly, Kevin overs the last 1/3 of the distance in 4 seconds, at a constant acceleration $a_k$ , we have the following equation of motion:

$s/3 = a_kt_k^2/2$

tk = 4 s is the time

$s = 3a_k4^2/2 = 24a_k$

$a_k = s/24$

Since $a_a = s/18$ we can conclude that $a_a > a_k$ , so Alison would win.

The time it takes for Alison to cover the entire track

$s = a_aT_a^2/2$

$T_a^2 = 2s/a_a = 2s/(s/18) = 36$

$T_a = \sqrt{36} = 6 s$

The time it takes for Kevin to cover the entire track

$s = a_kT_k^2/2$

$T_k^2 = 2s/a_k = 2s/(s/24) = 48$

$T_a = \sqrt{48} = 6.93 s$

So Alison wins against Kevin by 6.93 - 6 = 0.93 s

4 0

3 years ago

Need help will give brianly

Katen [24]

3. No it is not on the graph.

because: y=2x+5 insert (5,6)

6=2x5 +5 is wrong

4. C

8 0

3 years ago