Question

A candy store wants to create a mix of two hard candies. One is priced at $5.45 per pound, and the other is priced a $7.33 per pound. How many pounds of the $7.33 candy should be mixed with 11 pounds of the $5.45 candy to sell the mixture for $6.14 per pound.
Solve and explain please. 
Also make an equation first. Thanks.

Answer 1

$x-\ amount\ of\ candy\ which\ cost\ 5,45\ \\\\y-\ amount\ of\ candy\ which\ cost\ 7,33\ \\\\ 7,33*y+11*5,45=6,14(11+y)\\\\ 7,33y+59,95=67,54+6,14y\ \ \ \ | subtract\ 6,14y\\\\ 1,19y=67,54-59,95\\\\ 1,19y=7,59\ \ \ \ | divide\ by\ 1,19\\\\y=6,38\ pound\\\\ 6,38\ pounds\ should\ be\ mixed\ with\ those\ wich\ cost\ 5,45.$