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1 year ago

Sat question solve 2^x=x^2

1 answer:

Ivan1 year ago

7 0

The logarithm function can be used to convert large problem of multiplication and division into simple addition or subtraction. The value of x for the given equation is 2.

<h3>What is Logarithm? </h3>

Logarithm function is defined as the inverse of the exponential function.

If a^(b) = c, then b = log(c) at the base of a.

The given equation is as below,

2^x=x^2

Take logarithm both sides,

x log(2) = 2 log(x)

=> x / log(x) = 2 / log(2)

Compare the denominator and numerator at both sides of the equation to get,

x = 2.

Hence the solution of the given equation is x = 2.

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Simplify 15/60 lowest answer

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1/4 or .25 or 25%
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4 years ago

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The table shows the income and expenses for a school carnival. The school’s go was to raise the $1300. Did the school reach its

vovangra [49]

No because if you add all of this up it equals 1077

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4 years ago

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Brilliant_brown [7]

Answer:

$f(x)=\sqrt{x-1}$ -----> Graph C

$f(x)=\sqrt{x}$ -----> Graph A

$f(x)=\sqrt{x}-1$ -----> Graph B

$f(x)=-\sqrt{x}$ -----> Graph D

$f(x)=-\sqrt{x-1}$ -----> Graph E

Step-by-step explanation:

we have

case a) $f(x)=\sqrt{x-1}$

Find the domain

we know that

The radicand must be greater than or equal to zero

$x-1\geq 0$

$x\geq 1$

The domain is the interval -----> [1,∞)

All real numbers greater than or equal to 1

The range is the interval -----> [0,∞)

All real numbers greater than or equal to 0

case b) $f(x)=\sqrt{x}$

Find the domain

we know that

The radicand must be greater than or equal to zero

$x\geq 0$

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

The range is the interval -----> [0,∞)

All real numbers greater than or equal to 0

case c) $f(x)=\sqrt{x}-1$

Find the domain

we know that

The radicand must be greater than or equal to zero

$x\geq 0$

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

The range is the interval -----> [-1,∞)

All real numbers greater than or equal to -1

case d) $f(x)=-\sqrt{x}$

Find the domain

we know that

The radicand must be greater than or equal to zero

$x\geq 0$

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

The range is the interval -----> (-∞,0]

All real numbers less than or equal to 0

case e) $f(x)=-\sqrt{x-1}$

Find the domain

we know that

The radicand must be greater than or equal to zero

$x-1\geq 0$

$x\geq 1$

The domain is the interval -----> [1,∞)

All real numbers greater than or equal to 1

The range is the interval -----> (-∞,0]

All real numbers less than or equal to 0

5 0

3 years ago

Carl collects coins compulsively, but he only likes quarters and dimes. Carl currently has 125 coins for a total of $26.00. How

faust18 [17]

We need to find the two equations that represents the total amount of coins Carl has that makes $26.00 and the number of quarters and dimes.

Carl has 35 dimes and 90 quarters. The equations are $0.1x+0.25y=26$ and $x+y=125$ .

Let the number of dimes be $x$

Let the number of quarters be $y$

The total number of coins is $125$

So, the first equation will be

$x+y=125$

The value of the coins is $26. So,

$0.1x+0.25y=26$

Let us solve the equations

$x=125-y$

$0.1\times (125-y)+0.25y=26\\\Rightarrow 12.5-0.1y+0.25y=26\\\Rightarrow 0.15y=13.5\\\Rightarrow y=\dfrac{13.5}{0.15}\\\Rightarrow y=90$

$x+y=125\\\Rightarrow x=125-90\\\Rightarrow x=35$

The number of dimes is 35 and the number of quarters is 90.

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3 years ago

What is m∠KNL?<br> Enter answer in box

kodGreya [7K]

I want to talk about X's. I'll start by talking about this X - a cross (photo 1). Specifically, a cross made of two perpendicular lines - lines that meet each other at right angles all around. What's special about a cross? There's the religious significance, but in our case, there's also the <em>symmetry</em>. The quick, intuitive definition of symmetry is some quality that a thing has where, if you do something to it, it'll still look the same. Your body is symmetric; the left side of our bodies looks like we took the right side and flipped it - they're mirror images of each other.

One of the symmetries of this cross is right here. (Picture 2) It splits the cross into <em>two identical halves</em>, one a mirror image of the other. Most importantly, <em>the angles on each side of the line are identical</em>. We can draw this same mirror into our problem, too (picture 3). This symmetry tells us that those two unknown angles are exactly the same - <em>equal</em>. So, if angle MNJ is 5x+2 and angle LNK is 3(x+14), we now know that

5x + 2 = 3(x + 14), or, getting our algebra sorted:

5x + 2 = 3x + 42

2x = 40

x = 20

Now that we know x, we can find MNJ - which, because X's are symmetric, is exactly the same angle as LNK. Crunching the numbers, we find

m∠MNJ = m∠LNK = 5(20) + 2 = 100 + 2 = 102°.

Side note: the technical term for pairs of angles like MNJ and LNK is vertical angles. What we've shown here is, because of the symmetry of intersecting lines, vertical angles are always equal.

7 0

3 years ago