Answer:
<em>8(x2 + 2x) = –3
</em>
<em>8(x2 + 2x + 1) = –3 + 8
</em>
<em>x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot</em>
Step-by-step explanation:
<u>Solving Quadratic Equations
</u>
Sometimes it's preferred to solve quadratic equations without the use of the known quadratic formula solver. One of the most-used methods consists of completing squares and solving for x.
We have the equation
We separate variables from constants
Taking the common factor 8
Completing squares in the brackets and balancing the equation in the right side
Factoring the perfect square
Isolating x
We can clearly see the steps used to solve the quadratic equation are (in order and written like in the question)
8(x2 + 2x) = –3
8(x2 + 2x + 1) = –3 + 8
x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot
Answer twenty nine the answers 29 because 4 + 8=12+6=29
An equation of a line parallel to y=x-6, must have the same slope.
In this equation:
y=mx+b (slope-intercept form)
m is the slope:
The slope of the equation y=x-6 is m=1 (the number beside "x").
Now we have a point (-1,5) and the slope m=1.
Point-slope form of a line:
y-y₀=m(x-x₀)
so:
y-5=1(x+1)
answer: the equation of the line in point-slope form is :
y-5=1(x+1)
And the eqution of this line in slope-intercept form is:
y=x+6
y-5=(x+1)
y=x+1+5
y=x+6
Answer:
The mean squares has d.f (n-1)
Step-by-step explanation:
The total number of degrees of freedom is n-1 as there is only one restriction of computing the grand mean. The d.f for k samples is k-1 beacuase the mean of the sample means must equal the grand mean. Similarly , the d.f for within SS is n-k , due to the k restrictions of computing the k sample means. Hence we find that
Total df= Within df + Between df
n-1= (n-k)+(k-1)
Between SS has (k-1) d.f
Within SS has (n-k) d.f
These two quantities are known as mean squares and has d.f (n-1)
Answer:
Step-by-step explanation:
